All categories

4 years ago

How does the matter and energy in a system naturally change over time?

1 answer:

3 0

If there is no input to the system and no leaks from it, then the matter and energy in the system naturally does not change over time

You might be interested in

The electrons in a particle beam each have a kinetic energy K. What is the magnitude of the electric field that will stop these

harina [27]

Answer:

Electric field magnitude

E = K/qd

Where

K = kinetic energy of electron

d = electron distance

q = charge

Explanation:

Given the relationship between workdone and energy

Work-energy theorem:

Net workdone = Energy change

W = ∆E

In this case

W = ∆K.E

And,

∆K.E = K(final) - K(initial)

To stop the kinetic energy | K(final) = 0

K(initial) = K (given)

∆K.E = 0 - K = -K

Let the electric force on the electron has magnitude F.

And

W = -Fd = ∆K.E = -K

-Fd = -K

F = K/d .....1

The magnitude of the electric field E that can stop these electron in a distance d:

E = F/q ......2

Where q is the charge on electron.

substituting equation 1 to 2

E = (K/d)/q = K/qd

E = K/qd

3 0

4 years ago

One long wire carries a current of 30 A along the entire x axis. A second long wire carries a current of 40 A perpendicular to t

WINSTONCH [101]

Complete question is;

One long wire carries a current of 30 A along the entire x axis. A second long wire carries a current of 40 A perpendicular to the xy plane and passes through the point (0, 4, 0) m. What is the magnitude of the resulting magnetic field at the point y = 2.0 m on the y axis?

Answer:

B_net = 50 × 10^(-7) T

Explanation:

We are told that the 30 A wire lies on the x-plane while the 40 A wire is perpendicular to the xy plane and passes through the point (0,4,0).

This means that the second wire is 4 m in length on the positive y-axis.

Now, we are told to find the magnitude of the resulting magnetic field at the point y = 2.0 m on the y axis.

This means that the position we want to find is half the length of the second wire.

Thus, at this point the net magnetic field is given by;

B_net = √[(B1)² + (B2)²]

Where B1 is the magnetic field due to the first wire and B2 is the magnetic field due to the second wire.

Now, formula for magnetic field due to very long wire is;

B = (μ_o•I)/(2πR)

Thus;

B1 = (μ_o•I_1)/(2πR_1)

Also, B2 = (μ_o•I_2)/(2πR_2)

Now, putting the equation of B1 and B2 into the B_net equation, we have;

B_net = √[((μ_o•I_1)/(2πR_1))² + ((μ_o•I_2)/(2πR_2))²]

Now, factorizing out some common terms, we have;

B_net = (μ_o/2π)√[((I_1)/R_1))² + ((I_2)/R_2))²]

Now,

μ_o is a constant and has a value of 4π × 10^(−7) H/m

I_1 = 30 A

I_2 = 40 A

Now, as earlier stated, the point we are looking for is 2 metres each from wire 2 end and wire 1.

Thus;

R_1 = 2 m

R_2 = 2 m

So, let's calculate B_net.

B_net = ((4π × 10^(−7))/2π)√[(30/2)² + (40/2)²]

B_net = 50 × 10^(-7) T

5 0

3 years ago

Which one is correct:

alisha [4.7K]

Answer:

Option (c) is correct.

Explanation:

Acceleration of an object is given by the formula as follows :

$a=\dfrac{v-u}{t}$

Where

u and v are initial and final velocity

t is time

(v-u) is also called the change in velocity

So, the acceleration of an object is equal to the rate of change of velocity. Hence, the correct option is (c) " Change in its velocity divided by the change in time".

3 0

3 years ago

The rate of change of momentum?

Blizzard [7]

Answer:

Answer in below and plz mark me as brainlist plz

Explanation:

The rate of change of momentum =tm(v−u) Rate of change of momentum = force applied. Force∝tm(v−u) Velocity is the rate of change of displacement and acceleration is the rate of change of velocity. Impulse is a change in momentum

6 0

3 years ago

A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci

Drupady [299]

Answer:

<em>The resultant velocity has a magnitude of 38.95 m/s</em>

Explanation:

<u>Vector Addition</u>

Given two vectors defined as:

$\vec v_1=(x_1,y_1)$