<span>The flywheel is solid cylindrical disc. Moment of inertial = ½ * mass * radius^2
Mass = 40.0 kg
Radius = ½ * 76.0 cm = 38 cm = 0.38 meter
Moment of inertial = ½ * 41 * 0.36^2
Convert rpm to radians/second
The distance of 1 revolution = 1 circumference = 2 * π * r
The number of radians/s in 1 revolution = 2 * π
1 minute = 60 seconds
1 revolution per minute = 2 * π radians / 60 seconds = π/30 rad/s
Initial angular velocity = 500 * π/30 = 16.667 * π rad/s
170 revolutions = 170 * 2 * π = 340 * π radians
The flywheel’s initial angular velocity = 16.667 * π rad/s. It decelerated at the rate of 1.071 rad/s^2 for 48.89 seconds.
θ = ωi * t + ½ * α * t^2
θ = 16.667 * π * 48.89 + ½ * -1.071 * 48.89^2
2559.9 - 1280
θ = 1280 radians</span>
Answer:
Explanation:
Given
Electric Field 
velocity 
mass of electron 
Force on a charge Particle moving in Magnetic Field
![F=e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]](https://tex.z-dn.net/?f=F%3De%5Cleft%20%5B%20%5Cvec%7BE%7D%2B%5Cleft%20%28%20%5Cvec%7Bv%7D%5Ctimes%20%5Cvec%7BB%7D%5Cright%20%29%5Cright%20%5D)
![a=\frac{e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]}{m}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Be%5Cleft%20%5B%20%5Cvec%7BE%7D%2B%5Cleft%20%28%20%5Cvec%7Bv%7D%5Ctimes%20%5Cvec%7BB%7D%5Cright%20%29%5Cright%20%5D%7D%7Bm%7D)
![a=\frac{1.6\times 10^{-19}\left [ 2\hat{i}+5.4\hat{j}+\left ( 8\hat{i}\times 0.4\hat{k}\right )\right ]}{9.1\times 10^{-31}}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B1.6%5Ctimes%2010%5E%7B-19%7D%5Cleft%20%5B%202%5Chat%7Bi%7D%2B5.4%5Chat%7Bj%7D%2B%5Cleft%20%28%208%5Chat%7Bi%7D%5Ctimes%200.4%5Chat%7Bk%7D%5Cright%20%29%5Cright%20%5D%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%7D)
V = IR
Where v is voltage I is current and r is resistance
So
V = 9
R = 12
V/R = I
9/12 = I
I = 0.75 A
Explanation:
Use the height of the cliff to determine how long it took the car to land.
Take down to be positive. Given:
Δy = 7.93 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
7.93 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 1.27 s
Use the time to calculate the horizontal velocity.
Given:
Δx = 26.7 m
a = 0 m/s²
Find: v₀
Δx = v₀ t + ½ at²
26.7 m = v₀ (1.27 s) + ½ (0 m/s²) (1.27 s)²
v₀ = 21.0 m/s
The driver was going 21.0 m/s, faster than the speed limit of 9.72 m/s.
Answer:
both technician A and Technician B are correct
Explanation:
Technician A says balance shafts are used to counteract vibration created in the engine. Technician B says proper balancing of the engine is important for smooth operation. Which technician is correct
In piston engine engineering, a balance shaft is an eccentric weighted shaft that counteracts vibrations in engine designs that are not inherently balanced. They were first invented and patented by British engineer Frederick W. Lanchester in 1904. ... .The balance shafts have eccentric weights and rotate in opposite direction to each other, which generates a net vertical force. Unavailability of the balance shaft can cause excessive vibration to the engine thereby damaging the oil pump and resulting to engine failure.
