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Marat540 [252]
2 years ago
15

What is the period of vibration for a wave with a frequency of 100 hertz?

Physics
2 answers:
Taya2010 [7]2 years ago
5 0

Answer:

100 seconds

Hope this Helps :)

Dmitriy789 [7]2 years ago
3 0

The number of back-and-forth vibrations in a unit of time is an object's frequency. A complete back-and-forth vibration is one cycle. 1 Hz is one vibration or wave cycle per second!

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In 1610, galileo used his telescope to discover four prominent moons around jupiter. their mean orbital radii a and periods t ar
katrin2010 [14]

Time period of any moon of Jupiter is given by

T = 2\pi \sqrt{\frac{r^3}{GM}}

from above formula we can say that mass of Jupiter is given by

M = \frac{4 \pi^2 r^3}{GT^2}

now for part a)

r = 4.22 * 10^8 m

T = 1.77 day = 152928 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (4.22 * 10^8)^3}{(6.67 * 10^{-11})(152928)^2}

M = 1.9* 10^{27} kg

Part B)

r = 6.71 * 10^8 m

T = 3.55 day = 306720 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (6.71 * 10^8)^3}{(6.67 * 10^{-11})(306720)^2}

M = 1.9* 10^{27} kg

Part c)

r = 10.7 * 10^8 m

T = 7.16 day = 618624 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (10.7 * 10^8)^3}{(6.67 * 10^{-11})(618624)^2}

M = 1.89* 10^{27} kg

PART D)

r = 18.8 * 10^8 m

T = 16.7 day = 1442880 seconds

now by above formula

M = \frac{4 \pi^2 r^3}{GT^2}

M = \frac{4 \pi^2 (18.8 * 10^8)^3}{(6.67 * 10^{-11})(1442880)^2}

M = 1.889* 10^{27} kg

6 0
3 years ago
I NEED THIS A SOON AS POSSIBLE
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Work is done when spring is extended or compressed. Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened, the work done is equal to the elastic potential energy stored.

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Answer:

it is320 m.

Explanation:

by formula

d= m/s×t

d= 8× 40

d=320 m

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Answer:

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1. the most suitable cutting process to use on ferrous metals such as straight carbon steel is
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Answer:

plasma arc

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Explanation:

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