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Vinil7 [7]
3 years ago
15

ПОМОГИТЕ ПЖЖППЖЖППЖЖПЖЖПЖПЖПЖ ООООООЧЕНЬ СРОЧНО!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! С ДАНО И РЕШЕНИЕМ!!!!!!

Physics
1 answer:
wel3 years ago
4 0

Answer:

thanks for the points dia

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In the generation of most anions, the energy change (kj/mol that _______ an electron is ________.
g100num [7]
Released                       taken in
<span>Anion are associated with exothermic process.</span>

7 0
3 years ago
A 30 kg child sitting 5.0 m from the center of a merry-go-round has a constant speed of 5.0 m/s. while she remains seated in the
expeople1 [14]

Let us say that v is the tangential velocity of the object, a to be the centripetal (which acts towards the center of the circle) acceleration and F as the centripetal force, r to be the radius of the circle and m is mass of the child. <span>

a = v^2 / r 

F = ma = mv^2/r 

Applying the given values to the equation: 

F=30*(5^2/5) => 30*(25/5) => 30*5 => 150 Newtons</span>

Now work is Force times distance, the distance is simply the circumference of the circle.

d = C = 2 * pi * r = 2 * pi * 5 = 10π m

 

W = F * d = 150 N * 10π m

<span>W = 1500π J = 4712.39 J</span>

8 0
3 years ago
At what speed, as a fraction of c , is a particle's total energy twice its rest energy
WINSTONCH [101]
The rest energy of a particle is
E_0=m_0 c^2
where m_0 is the rest mass of the particle and c is the speed of light.

The total energy of a relativistic particle is
E=mc^2 =  \frac{m_0 c^2}{ \sqrt{1- \frac{v^2}{c^2} } }
where v is the speed of the particle.

We want the total energy of the particle to be twice its rest energy, so that
E=2E_0
which means:
\frac{m_0c^2}{ \sqrt{1- \frac{v^2}{c^2} } }=2m_0 c^2
\frac{1}{ \sqrt{1- \frac{v^2}{c^2} } }=2
From which we find the ratio between the speed of the particle v and the speed of light c:
\frac{v}{c}=  \sqrt{1- (\frac{1}{2})^2 }  =0.87
So, the particle should travel at 0.87c in order to have its total energy equal to twice its rest energy.
3 0
3 years ago
Susie rides down and to the right on a slide for a total displacement of -3m at an angle of 45 degrees above the ground. What wa
Svetlanka [38]

Susie's vertical displacement is 2.1 m

Explanation:

In order to solve this problem, we have to resolve the displacement vector along the vertical direction.

The vertical component of a vector is given by:

v_y = v sin \theta

where

v is the magnitude of the vector

\theta is the angle between the direction of the vector and the horizontal

Therefore, the vertical  component of the displacement in this problem is given by

d_y = d sin \theta

where

d = 3 m is the magnitude of the displacement

\theta=45^{\circ} is the angle between the  displacement and the horizontal

Substituting, we find

d_y = (3)(sin 45^{\circ})=2.1 m

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

6 0
4 years ago
A cyclotron is designed to accelerate protons (mass 1.67 x 10^-27 kg) up to a kinetic energy of 2.5 x 10^-13 J. If the magnetic
Dafna11 [192]

Answer:

24 cm

Explanation:

Given:

Mass of proton = 1.67 × 10⁻²⁷ Kg

kinetic energy = 2.5 × 10⁻¹³ J

magnetic field in the cyclotron, B = 0.75 T

Now,

Kinetic energy = \frac{1}{2}mv^2  = 2.5 × 10⁻¹³ J

where, v is the velocity of the electron

or

\frac{1}{2}\times1.67\times10^{-27}\times v^2  = 2.5 × 10⁻¹³ J

or

v² = 2.99 × 10¹⁴

or

v = 1.73 × 10⁷ m/s

also,

centripetal force = magnetic force

or

\frac{mv^2}{r}  = qvB

q is the charge of the electron

r is the radius of the dipole magnets

on substituting the respective values, we get

\frac{1.67\times10^{-27}\times1.73\times10^7}{r}  = 1.6 × 10⁻¹⁹ × 0.75

or

r = 0.2408 m ≈ 24 cm

Hence, the correct answer is 24 cm

6 0
3 years ago
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