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kondaur [170]
3 years ago
5

A 30 kg child sitting 5.0 m from the center of a merry-go-round has a constant speed of 5.0 m/s. while she remains seated in the

same spot and travels in a circle, the work the seat performs on her in one complete rotation is
Physics
1 answer:
expeople1 [14]3 years ago
8 0

Let us say that v is the tangential velocity of the object, a to be the centripetal (which acts towards the center of the circle) acceleration and F as the centripetal force, r to be the radius of the circle and m is mass of the child. <span>

a = v^2 / r 

F = ma = mv^2/r 

Applying the given values to the equation: 

F=30*(5^2/5) => 30*(25/5) => 30*5 => 150 Newtons</span>

Now work is Force times distance, the distance is simply the circumference of the circle.

d = C = 2 * pi * r = 2 * pi * 5 = 10π m

 

W = F * d = 150 N * 10π m

<span>W = 1500π J = 4712.39 J</span>

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Answer: Friction between the two surfaces converts kinetic energy into thermal energy.

Explanation: Friction occurs because no surface is perfectly smooth. Rougher surfaces have more friction between them. Friction produces heat because it causes the molecules on rubbing surfaces to move faster and have more energy.

8 0
3 years ago
Conservation of Momentum
aksik [14]

Hi there!

This collision is an example of an inelastic collision since kinetic energy is lost from the collision.

We can represent this using the conservation of momentum formula:

m1v1 + m2v1 = m1vf + m2vf

Where:

m1 = blue ball

m2 = green ball

We know that the final velocity of the blue ball is 0, so:

m1v1 + m2v1 = m2vf

Rearrange to solve for the speed of the green ball:

(m1v1 + m2v1)/m2 = vf

Plug in given values:

((0.15 · 3) + (0.15 · 2)) / 0.15 = 5 m/s

3 0
3 years ago
Johnny stretches a spring 40 cm from its resting position. The spring’s constant of proportionality is 20 N/m. What is the sprin
sergiy2304 [10]

The spring potential energy is 1.6 J

Explanation:

The elastic potential energy of a spring is given by the equation:

U = \frac{1}{2}kx^2

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U is the potential energy

k is the spring constant

x is the compression/stretching of the spring

For the spring in this problem, we have:

x = 40 cm = 0.40 m is the stretching

k = 20 N/m is the spring constant

Substituting into the equation, we can find the spring potential energy:

U=\frac{1}{2}(20)(0.40)^2=1.6 J

#LearnwithBrainly

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