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andrezito [222]
4 years ago
11

At a certain location, a gravitational force with

Physics
2 answers:
Elodia [21]4 years ago
8 0
The unit of gravitational field strength is Nkg^-1 ie N/kg because the formula for Gravitational field strength is g=F/m where F is the gravitational force and m is the mass, and so by process of elimination, the magnitude of the gravitational field strength at this location is:
5.0 N/kg



laiz [17]4 years ago
4 0

The correct answer is: Option (2) 5.0 N/kg

Explanation:

To find the magnitude of the gravitational field strength, you need the formula of weight, which is:

weight = mass * gravitational-field-strength

Where weight is in Newtons, mass is in kilograms and gravitational-field-strength is (Newtons per kilogram).

In this particular scenario, the gravitational force is equal to the weight; please do not confuse weight with a mass. Mass is 70 kg.

Plug in the values:

350 = 70 * gravitational-field-strength

gravitational-field-strength = 350/70

gravitational-field-strength = 5.0 N/kg (Option 2)

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To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 92.0 cm long (measured from the
lorasvet [3.4K]

Answer:

Xc = 64.27 cm, Yc = 0 cm, Xc = 27.73 cm, Yc = 18.27 cm

Explanation:

A human leg is 92 cm long equally divided into two parts (upper leg and lower leg) that is both are 46 cm long

M1 = 8.35 kg

M2 = 5.50 kg

A. Starting from hip joint, when the leg is placed horizontally, the X coordinate of centre of mass will be

Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50 x 92) / 8.35 + 5.50

( here we took x2 = 92 cm because we are measuring length from the hip joint, that means length at hip joint is 0 and at the foot 92 cm)

Xc = 890.1 / 13.85

Xc = 64.27 cm

B. Yc = (y1m1 + y2m2) / m1 + m2

Yc = (0x8.35 + 0x5.50) / 8.35 + 5.50

( here y1 and y2 are 0 because the leg is placed horizontally that means in X direction so none of the leg component is in Y direction)

Yc = 0 cm

C. Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50x0) / 8.35 + 5.50

(here x2 is taken 0 because the other half leg is bent vertically that means it is in Y direction so its X component is 0)

Xc = 384.1 / 13.85

Xc = 27.73 cm

D. Yc = (m1y1 + m2y2) / m1 + m2

Yc = (8.35x0 + 5.50x46) / 8.35 + 5.50

(here y1 is zero because the upper leg is in X direction and y2 is taken 46 cm because starting measuring from hip joint 46 cm of length of lower leg is in Y direction)

Yc = 253/13.85

Yc = 18.27 cm

7 0
3 years ago
Which of the following would most likely utilize a particulate control device?
Alexandra [31]

Answer:

d

Explanation:

Correct answer: D). All of the above The particulate control device is a device that is used for the separation of the material that is of a bigger size as compared to filter. In the factory smokestack, the particulate control device filters the particulate matter that is known to cause air pollution. In the vacuum cleaner, a fine dust particle is filtered out. In the laundry dryer, the water and dirt molecule is allowed to pass through it. Hence, all the options are correct.so therefore your answer would be all

3 0
3 years ago
Read 2 more answers
Plssss help I need good grade!!!! Plssss and thank u
shepuryov [24]

Answer:

the answer is 'b'

According to me

8 0
3 years ago
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De acuerdo a la trayectoria que describe el movimiento de la
dusya [7]

Answer:

With a circle.

Explanation:

8 0
3 years ago
Assume that a particle moves in a velocity field defined by V (x, y) = (x + 6)i + (y − 3)j. Find the path of a particle with ini
gladu [14]

Answer:

V(1,1)=7i-2j

Explanation:

V(x,y)=(x+6)i+(y-3)j ............eq1

As intial point are given (1,1)

which means x=1,y=1

put these values in eq1

V(1,1)=(1+6)i+(1-3)j

V(1,1)=7i-2j

And its magnitude given as

|V(1,1)|=\sqrt{(7)^{2}+(-2)^{2}  }

|V(1,1)| =7.28

8 0
3 years ago
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