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3 years ago

At a certain location, a gravitational force with

2 answers:

8 0

The unit of gravitational field strength is Nkg^-1 ie N/kg because the formula for Gravitational field strength is g=F/m where F is the gravitational force and m is the mass, and so by process of elimination, the magnitude of the gravitational field strength at this location is:
5.0 N/kg

laiz [17]3 years ago

4 0

The correct answer is: Option (2) 5.0 N/kg

Explanation:

To find the magnitude of the gravitational field strength, you need the formula of weight, which is:

weight = mass * gravitational-field-strength

Where weight is in Newtons, mass is in kilograms and gravitational-field-strength is (Newtons per kilogram).

In this particular scenario, the gravitational force is equal to the weight; please do not confuse weight with a mass. Mass is 70 kg.

Plug in the values:

350 = 70 * gravitational-field-strength

gravitational-field-strength = 350/70

gravitational-field-strength = 5.0 N/kg (Option 2)

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How do you find the missing terms in a number sentence?

FrozenT [24]

Determine the rule that the numbers in the sequence obey, and then utilize this rule to determine the missing term to complete a number sequence. The rule that the numbers in the example above adhere to is "Add 8 and then remove 2." Therefore, 32 is the term that is missing from the given number sequence.

<h3>What is a number sentence?</h3>

A number sentence is an equation or inequality that is articulated using numbers and mathematical symbols in the context of mathematics education.
In the US, Canada, UK, Australia, New Zealand, South Africa, and other countries, the phrase is used in the instruction of elementary-level mathematics.
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To introduce pupils to the ideas of structure and basic algebra before more formal teaching of these concepts, number sentences are utilized.

<h3>A math sentence is what?</h3>

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5 0

1 year ago

A wire has a cross sectional area of 4.00 mm2 and is stretched by 0.100 mm by a certain force. How far will a wire of the same m

Nina [5.8K]

Answer: $0.05\ mm$

Explanation:

Given

Cross-sectional area of wire $A_1=4\ mm^2$

Extension of wire $\delta l=0.1\ mm$

Extension in a wire is given by

$\Rightarrow \delta l=\dfrac{FL}{AE}$

where, $E=\text{Youngs modulus}$

$\Rightarrow \delta_1=\dfrac{FL}{A_1E}\quad \ldots(i)$

for same force, length and material

$\Rightarrow \delta_2=\dfrac{FL}{A_2E}\quad \ldots(ii)$

Divide (i) and (ii)

$\Rightarrow \dfrac{0.1}{\delta_2}=\dfrac{A_2}{A_1}\\\\\Rightarrow \delta_2=0.1\times \dfrac{4}{8}\\\\\Rightarrow \delta_2=0.05\ mm$

5 0

2 years ago

If Star A is magnitude 1.0 and Star B is magnitude 9.6 , which is brighter and by what factor?

ludmilkaskok [199]

Answer:

Star A is brighter than Star B by a factor of 2754.22

Explanation:

Lets assume,

the magnitude of star A = m₁ = 1

the magnitude of star B = m₂ = 9.6

the apparent brightness of star A and star B are b₁ and b₂ respectively

Then, relation between the difference of magnitudes and apparent brightness of two stars are related as give below: $(m_{2} - m_{1}) = 2.5\log_{10}(b_{1}/b_{2})$

The current magnitude scale followed was formalized by Sir Norman Pogson in 1856. On this scale a magnitude 1 star is 2.512 times brighter than magnitude 2 star. A magnitude 2 star is 2.512 time brighter than a magnitude 3 star. That means a magnitude 1 star is (2.512x2.512) brighter than magnitude 3 bright star.

We need to find the factor by which star A is brighter than star B. Using the equation given above,

$(9.6 - 1) = 2.5\log_{10}(b_{1}/b_{2})$

$\frac{8.6}{2.5} = \log_{10}(b_{1}/b_{2})$

$\log_{10}(b_{1}/b_{2}) = 3.44$

Thus,

$(b_{1}/b_{2}) = 2754.22$

It means star A is 2754.22 time brighter than Star B.

3 0

3 years ago

A student conducts an experiment in which a cart is pulled by a variable applied force during a 2 s time interval. In trial 1, t

fredd [130]

Answer:

The answer is "Including all three studies of 0s to 2s, that shift in momentum is equal".

Explanation:

Its shift in momentum doesn't really depend on the magnitude of its cars since the forces or time are similar throughout all vehicles.

Let's look at the speed of the car

$F = m a\\\\a =\frac{F}{m}$

We use movies and find lips

$\to v = v_0 + a t\\\\\to v = v_0 + (\frac{F}{m}) t$

The moment is defined by

$\to p = m v$

The moment change

$\Delta p = m v - m v_0$

Let's replace the speeds in this equation

$\Delta p = m (v_0 + \frac{F}{m t}) - m v_0\\\\\Delta p = m v_0 + F t - m v_0\\\\\Delta p = F t$

They see that shift is not directly proportional to the mass of cars since the force and time were the same across all cars.

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3 years ago

What ia the law of convesation of energy

Free_Kalibri [48]

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. This law means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.

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3 years ago