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andrezito [222]
3 years ago
11

At a certain location, a gravitational force with

Physics
2 answers:
Elodia [21]3 years ago
8 0
The unit of gravitational field strength is Nkg^-1 ie N/kg because the formula for Gravitational field strength is g=F/m where F is the gravitational force and m is the mass, and so by process of elimination, the magnitude of the gravitational field strength at this location is:
5.0 N/kg



laiz [17]3 years ago
4 0

The correct answer is: Option (2) 5.0 N/kg

Explanation:

To find the magnitude of the gravitational field strength, you need the formula of weight, which is:

weight = mass * gravitational-field-strength

Where weight is in Newtons, mass is in kilograms and gravitational-field-strength is (Newtons per kilogram).

In this particular scenario, the gravitational force is equal to the weight; please do not confuse weight with a mass. Mass is 70 kg.

Plug in the values:

350 = 70 * gravitational-field-strength

gravitational-field-strength = 350/70

gravitational-field-strength = 5.0 N/kg (Option 2)

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Answer:

His final velocity is 15.8 m/s.

Step-by-step explanation:

Given:

Initial velocity of the driver is, u=32 m/s

Acceleration of the driver is, a=-1.5 m/s²

Time taken to reach final velocity is, t=10.8 s.

The final velocity is given using the Newton's equations of motion as:

v=u+at, where, v is the final velocity.

Now, plug in the given values and solve for v.

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3 years ago
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Answer:

T = 60 s

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vova2212 [387]

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