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3 years ago

What causes water molecules to be attracted to each other?

Physics

1 answer:

mars1129 [50]3 years ago

3 0

Answer:

the positive and negative charges of the hydrogen and oxygen atoms that make up water molecules makes them attracted to each other

Explanation:

Hope this helps dude

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PLEASE HELP NEED TO KNOW IF CORRECT!! BRAINLIEST ANSWER WILL BE REWARDED.

melisa1 [442]

The correct answer is transmission<<<<<<

8 0

4 years ago

A car traveling 20 m/s to the north collides with a car traveling 10 m/s to the

sergiy2304 [10]

Answer: C

Explanation:

In collision, whether elastic or inelastic collisions, momentum is always conserved. That is, the momentum before collision will be equal to the momentum after collision.

Change in momentum of the system will be momentum after collision minus total momentum before collision.

Since momentum is a vector quantity, the direction will also be considered.

Momentum = MV - mU

Let

M = 800 kg is going north

at V = 20 m/s and the other car

m= 800 kg is going south

at U = 10m/s.

Substitute all the parameters into the formula

Momentum = (800 × 20) - (800 × 10)

= 8000 kgm/s

The final momentum after collision will also be equal to 8000 kgm/s

Change in momentum = 8000 - 8000

Change in momentum = 0

5 0

3 years ago

Read 2 more answers

Of the 50 U.S. states, 4 have names that start with the letter W.

professor190 [17]

Answer:

Explanation:

Divide 4 by 50,

4/50=0.08

0.08 as a percent is 8%

8 0

3 years ago

Read 2 more answers

A bat emits a sound at a frequency of 30.0 kHz as it approaches a wall. The bat detects beats such that the frequency of the ech

Alex

Answer:

The speed of the bat is 5.02 m/s.

Explanation:

Given that,

Frequency = 30.0 kHz

Frequency of echo = 900 Hz

We need to calculate the frequency

Using formula of beat frequency

$f_{b}=f_{1}-f_{2}$

Put the value into the formula

$900=f_{1}-30\times10^{3}$

$f_{1}=900+30000$

$f_{1}=30900\ Hz$

We need to calculate the speed of the bat

Using Doppler equation

$f_{apr}=f\times(\dfrac{v_{sound}+v_{observer}}{v_{s}-v_{source}})$

Put the value into the formula

$30900=30000\times(\dfrac{340+v_{bat}}{340-v_{bat}})$

$\dfrac{30900}{30000}=\dfrac{340+v_{bat}}{340-v_{bat}}$

$1.03=\dfrac{340+v_{bat}}{340-v_{bat}}$

$340\times1.03-340=v_{b}+1.03v_{b}$

$10.2=2.03v_{bat}$

$v_{bat}=\dfrac{10.2}{2.03}$

$v_{bat}=5.02\ m/s$

Hence, The speed of the bat is 5.02 m/s.

6 0

3 years ago

A wave traveling at 230 m/sec has a wavelength of 2.1 meters. What is the frequency of this wave?

Galina-37 [17]

Answer:

Explanation:

The frequency of the wave when given it's velocity and wavelength only can be found by using the formula

$f = \frac{c}{ \lambda} \\$

where

c is the velocity of the wave in m/s

$\lambda$ is the wavelength in meters

From the question we have

c = 230 m/s

$\lambda$ = 2.1 m

$f = \frac{230}{2.1} = 109.523809... \\$

We have the final answer as

Hope this helps you

3 0

3 years ago