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3 years ago

PLEASE HELP!!!!

2 answers:

7 0

Answer:

4/9

Solution:

117-36 = 81
So out of the 117 books checked out, 36 of them were fiction and 81 were non-fiction, 36/81 simplified to lowest terms is 4/9

KengaRu [80]3 years ago

3 0

36:81

117 - 36 = 81

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83% of ____=75.53 this is for my math ixl

Katarina [22]

Answer:

83% of 91 = 75.53

5 0

3 years ago

An outside thermometer reads -4 degrees at 7:00 a.m. By 2:30 p.m. the temperature outside has increased by 11 degrees. At 2:30 p

Gnesinka [82]

Answer:

-169 degrees

Step-by-step explanation:

It doesn't make much sense... but let's answer the question anyway.

First task is to determine what's the temperature outside at 2:30 PM.

We know that it's 11 degrees cooler than it was at 7 AM, so -4 - 11 = -15 degrees.

Abram's house is 4 degrees less than 11 times the outside temperature, so we can express that as:

House = 11 x - 4 - where x is the temperature outside.

If we replace the numbers we get: 11 * (-15) - 4 = -165 - 4 = -169 degrees

Abram's house is an extremely cold freezer!

3 0

3 years ago

Read 2 more answers

Ms. Caldwell went shopping and bought cute new dress that was 25% off the regular price. The amount of the discount was $5. What

joja [24]

Answer: The regular price of the shirt is $20.

Step-by-step explanation:

To find the regular price, find a number that 25% of it is equal to 5.

Solve using the equation,

25% * x = 5 Where x is the regular price.

0.25x = 5

x= 20

This means that the regular price is $20.

4 0

3 years ago

Factor the express using GCF 1. 54x - 30 2. 4+24

borishaifa [10]

Answer:

1) 6 (9x - 5)

2) 4 (1 + 6)

Step-by-step explanation:

1.

54x - 30

The greatest common factor is 6, hence take out 6

6 (9x - 5)

2.

4 + 24

The greatest common factor is 4, take out 4

4 (1 + 6)

*I am not simplifying this because as per what is given, I am unsure if one of these numbers is actually a coefficient.

8 0

3 years ago

Each side of a square is increasing at a rate of 8 cm/s. At what rate (in cm2/s) is the area of the square increasing when the a

statuscvo [17]

Answer:

Step-by-step explanation:

This is nice and simple. I'm going to walk through it like I do when teaching this concept to my class for the first time. This is a good problem for that.

We are given a square and we are looking for the rate at which the area is increasing when a certain set of specifics are given. That means that the main equation for this problem is the area of a square, which is:

$A=s^2$ where s is a side.

Since we are looking for the rate at which the area is changing, $\frac{dA}{dt}$ , we need to take the derivative of area formula implicitly:

$\frac{dA}{dt}=2s\frac{ds}{dt}$ that means that if $\frac{dA}{dt}$ is our unknown, we need values for everything else. We are given that the initial area for the square is 49. That will help us determine what the "s" in our derivative is. We plug in 49 for A and solve:

$49=s^2$ so

s = 7

We are also given at the start that the sides of this square are increasing at a rate of 8cm/s. That is $\frac{ds}{dt}$ . Filling it all in:

$\frac{dA}{dt}=2(7)(8)$ and

$\frac{dA}{dt}=112\frac{cm^2}{s}$

5 0

3 years ago

Read 2 more answers