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White raven [17]

3 years ago

11

9 ⋅ (−4) ⋅ (−4) ⋅ (−7) = ? 20 pts brainlyiest if correct

1 answer:

forsale [732]3 years ago

6 0

Answer:

The answer is -1008, it's in the comments

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The states C and D spend a total of $56.6 million for tourism. The state C spends $2.6 million more than the state D. Find the

igomit [66]

Answer:

State C : $30.9 Million State D : $25.7 Million

Step-by-step explanation:

It may help to just forget about the word "million" and focus on the decimal number part,so one you get the deciaml number you can just put the word million after it as your answer.

First do 56.6 divided by 2, which equals 28.3. Since it said that State C spends 2.6 million more, you hvae to add 28.3 and 2.6 together, which also equals 30.9. So now you know State C spends $30.9 million total. In order to find out how much money State D sends, you have to do 56.6 - 30.9,which comes up to 25.7. So finnaly you know that State C spends 30.9 million dollars and State D spends 25.7 million dollars.

5 0

3 years ago

The mean number of goals scored is 2.5.

LenaWriter [7]

Answer:

2 games.

Step-by-step explanation:

2.5 + 1.8 = 4

4 divided by 2 = 2

5 0

3 years ago

Multiply or divide as indicated. x^4 • x^-2

Anettt [7]

The answer is 0 unless I did the math wrong

If so someone correct me. Other than that, hope this helped!

8 0

3 years ago

Read 2 more answers

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

PLEASE HELP DUE IN 5 MINUTES!! NO LINKS! HELP WITH THE FIRST ONE ONLY!

PSYCHO15rus [73]

Answer:

PR=130, MPR=180, MRT=180, MT=130 HOPE THIS HELPED

Step-by-step explanation:

4 0

2 years ago