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Oduvanchick [21]
3 years ago
13

Which of the following is a perfect square trinomial?

Mathematics
2 answers:
svp [43]3 years ago
6 0
<h3>pa brainlist</h3>

<h3>C. 4x²+20xy+9y2</h3>

EastWind [94]3 years ago
6 0
Make an educated guess, as A would be a great guess. Lol
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The given lengths are two sides of a right triangle. All three side lengths of the triangle are integers and together form a pyt
Leni [432]
If all three side lengths are INTEGERS and form PYTHAGOREAN TRIPLE then we know decimals are not allowed

if 24 and 51 are both legs then
24^{2} +  51^{2} =  x^{2}
x = 3177
and squre root of that gives us 56.364.... NOT an integer

So that means one of them is not a leg and since hypotenuse is longer than both legs, 51 must be the hypotenuse so to get the third side

51^{2} -  24^{2}  =  x^{2}[tex] [tex] x^{2}=2025
x=45, leg B

7 0
3 years ago
There are 10 m of thread on the reel. She use 210 cm. In centimeters. How much is left on the reel
castortr0y [4]

Answer:

The length of the thread which is left on the reel is 790 cm. Used = 210 cm.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the volume ?
MatroZZZ [7]
<span><span>(<span><span>12</span><span>(<span>3+7</span>)</span></span>)</span><span>(3.5)</span></span><span>=<span><span><span>12</span><span>(<span>3+7</span>)</span></span><span>(3.5)</span></span></span><span>=<span><span><span>12</span><span>(<span>3+7</span>)</span></span><span>(3.5)</span></span></span><span>=<span><span>(<span><span>12</span><span>(10)</span></span>)</span><span>(3.5)</span></span></span><span>=<span><span>(5)</span><span>(3.5)</span></span></span><span>=17.5
</span>
7 0
4 years ago
This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
sleet_krkn [62]

Answer:

-6re−r [sin(6θ) - cos(6θ)]

Step-by-step explanation:

the Jacobian is ∂(x, y) /∂(r, θ) = δx/δθ × δy/δr - δx/δr × δy/δθ

x = e−r sin(6θ), y = er cos(6θ)

δx/δθ = -6rcos(6θ)e−r sin(6θ), δx/δr = -sin(6θ)e−r sin(6θ)

δy/δθ = -6rsin(6θ)er cos(6θ), δy/δr = cos(6θ)er cos(6θ)

∂(x, y) /∂(r, θ) =  δx/δθ × δy/δr - δx/δr × δy/δθ

= -6rcos(6θ)e−r sin(6θ) × cos(6θ)er cos(6θ) - [-sin(6θ)e−r sin(6θ) × -6rsin(6θ)er cos(6θ)]

= -6rcos²(6θ)e−r (sin(6θ) - cos(6θ)) - 6rsin²(6θ)e−r (sin(6θ) - cos(6θ))

= -6re−r (sin(6θ) - cos(6θ)) [cos²(6θ) + sin²(6θ)]

= -6re−r [sin(6θ) - cos(6θ)]     since  [cos²(6θ) + sin²(6θ)] = 1

6 0
4 years ago
SOLVE THIS PROBLEM, PLEASE! :(
pashok25 [27]

Answer:

1st Blank: 5

2nd Blank: 3

3rd Blank: -8

4th Blank: -8

5th Blank: 12

Step-by-step explanation:

15x+35y=-100

-15x+9y=-252

___________

44y=-352

___   ___

44       44

y=-8

3x+7(-8)=-20

3x-56=-20

   +56  +56

__________

3x=36

__  __

3     3

x=12

8 0
3 years ago
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