Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
Answer:
4 miles?
Step-by-step explanation:
Answer:
y = -x + 3
Step-by-step explanation:
First of all, you need to memorize several forms of the equation of a straight line. Here you have -2y - 2x = -6 in "standard form" and want the equivalent equation in "slope intercept form," y = mx + b.
To get this, solve the first equation for y by dividing all three terms by -2:
y + x = 3.
Then solve this result for y:
y = -x + 3
This is the desired equation in slope-intercept form.
If this is Textbook work- use SLADER (the app or the website)
