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frozen [14]
2 years ago
14

PLS HELP WILL MARK BRAINLIEST, PLS HURRY

Mathematics
2 answers:
Aleonysh [2.5K]2 years ago
8 0

its B

just for that pfp, be my wifey <33333

irina1246 [14]2 years ago
3 0

Answer:

B

Step-by-step explanation:

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Add your welcome I think
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2 years ago
How do you do this problem?
erastovalidia [21]

Step-by-step explanation:

∫₀² x f(x²) dx

If u = x², then du = 2x dx, and ½ du = x dx.

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2 years ago
A farmer sells 8.5 kilograms of apples and pears at the farmer's market. 4 5 of this weight is apples, and the rest is pears. Ho
slavikrds [6]

Answer:

your answer gonna be $13 dollars

6 0
2 years ago
Sorry again but i'm having trouble on this one
Lisa [10]

Answer:

m∠PNO = 60°

m∠O = 33°

Step-by-step explanation:

∡NPO is 87° because it's a vertical angle with the 87° angle

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5 0
2 years ago
A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro
Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let \mu be the true mean weight per apple the company ship.  We want to test the next hypothesis

H_{0}:\mu=120 vs H_{1}:\mu\neq 120 (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}} which is normally distributed. The observed value is  

z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583. The rejection region for \alpha = 0.05 is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.

5 0
3 years ago
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