PLS HELP WILL MARK BRAINLIEST, PLS HURRY
2 answers:
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Answer:
1)
the mean rate of return is 17 %
the standard deviation of return is 17.06055
2)
the probability that Marvin's portfolio will make at least 20% over the next 12 months is 0.4325
Step-by-step explanation:
Given the data in the question;
1)
For the portfolio, the mean return and standard deviation are computed as follows;
Mean = Return = 0.65 × 10 + 0.35 × 30
= 6.5 + 10.5
= 17 %
Therefore, the mean rate of return is 17 %
Standard deviation will be;
σp = √( 0.65² × 15² + 0.35² × 40² )
= √( 0.4225 × 225 + 0.1225 × 1600 )
= √( 95.0625 + 196 )
= √291.0625
= 17.06055
Therefore, the standard deviation of return is 17.06055
2)
probability that Marvin's portfolio will make at least 20% over the next 12 months.
P( X > 20 )
we convert to a standard normal variable;
Z = )
Z = 0.17
from z table, p-value is;
p( X < 20 ) = 0.5675
P( X > 20 ) 1 - 0.5675 = 0.4325
Therefore, the probability that Marvin's portfolio will make at least 20% over the next 12 months is 0.4325
Answer:
The Absolute Error is the difference between the actual and measured value.
The Relative Error is the Absolute Error divided by the actual measurement.
We know that the actual value is 102.0 mg/dL.
To find the absolute error and relative error for each measurement made by the glucose monitor you must use the above definitions.
a) For a concentration of 104.5 mg/dL the absolute error and relative error are
b) For a concentration of 96.2 mg/dL the absolute error and relative error are
c) For a concentration of 102.2 mg/dL the absolute error and relative error are
d) For a concentration of 98.3 mg/dL the absolute error and relative error are
e) For a concentration of 101.8 mg/dL the absolute error and relative error are