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2 years ago

How does the molecular geometry change if you replace a bond with a lone pair?

Chemistry

2 answers:

Musya8 [376]2 years ago

8 0

Answer:

The overall molecular shape (the molecule geometry) changes because of the lone pairs repulsion, <u>but the electron geometry does not change because whether an atom or a lone pair is added there's still two electrons being added.</u>

Explanation:

hope that helps :D

mihalych1998 [28]2 years ago

4 0

Answer:

Un par solitario o par de electrones no compartidos es un par de electrones de valencia que no se encuentra formando un enlace, ni compartido con otros átomos. Cuando un átomo se agrupa con otros para formar una molécula, sus electrones más externos -también conocidos como electrones de capa de valencia- dejan de pertenecer únicamente al átomo del que provienen, pasando a pertenecer a la molécula formada. Los orbitales atómicos de valencia dejan de existir como tales y pasan a formar orbitales moleculares con características diferentes a las originales. Como los pares solitarios se encuentran en la capa más externa de los átomos, cuando estos átomos forman moléculas pasan a formar parte del conjunto de electrones de valencia de la molécula. De esto se deduce que los pares solitarios son, de hecho, un subconjunto de los electrones de valencia de la molécula a la que pertenecen.

Explanation:

espero que te sirva :)

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3 years ago

What subatomic particle determines how an element reacts with another element?

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4 years ago

How many moles are in 3.45 g of Na2O?Round your answer to three significant

Neporo4naja [7]

Answer: There are 0.056 moles present in 3.45 g of $Na_{2}O$ .

Explanation:

Given : Mass = 3.45 g

Moles is the mass of substance divided by its molar mass.

Hence, moles of $Na_{2}O$ (molar mass = 61.98 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{3.45 g}{61.98 g/mol}\\= 0.056 mol$

Thus, we can conclude that there are 0.056 moles present in 3.45 g of $Na_{2}O$ .

6 0

3 years ago

What is the pH of 0.26 M ammonium ion? NH4+(aq) + H2O(1) NH3(aq) + H30* (aq) a. 4.33 b.9.25 c. 3.87 d. 4.92 e. 4.75

choli [55]

Answer:

b) pH = 9.25

Explanation:

NH4+(aq) + H2O(l) ↔ NH3(aq) + H3O+(aq)
NH3 + H2O ↔ NH4+ + OH-
2 H2O ↔ H3O+ + OH-

⇒ Kb = [ NH4+ ] * [ OH- ] / [ NH3 ] = 1.86 E-5......from literature

mass balance NH4+:

⇒ M NH4+ = [ NH4+ ] - [ OH- ]

∴ [ NH3 ] ≅ M NH4+ = 0.26 M

⇒ Kb = (( 0.26 + [ OH- ] )) * [ OH- ] / 0.26 = 1.86 E-5

⇒ 0.26 [ OH-] + [ OH- ]² = 4.836 E-6

⇒ [ OH- ]² + 0.26 [ OH- ] - 4.836 E-6 = 0

⇒ [ OH- ] = 1.859 E-5 M

⇒ pOH = - Log ( 1.859 E-5 )

⇒ pOH = 4.7305

⇒ pH = 14 - pOH = 9.269

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Alex73 [517]

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3 years ago