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nexus9112 [7]
3 years ago
12

Choose the predominant type of bonding as ionic, covalent, or metallic for the substance below. NiSn

Chemistry
1 answer:
podryga [215]3 years ago
8 0

Answer:

Metallic.

Explanation:

Hello,

In this case, when nickel and tin bond, the difference in their electronegativities results:

\Delta E=E_{Sn}-E_{Ni}=1.96-1.91=0.05

Such difference, in addition to the fact that nickel is a transition metal and tin a metal, will suggest that the predominant type of bond for this substance is metallic as the attractive force between the conduction of electrons and positively charged metal ions is present.

Best regards.

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7 0
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Alenkasestr [34]

Answer:

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4 0
3 years ago
Read 2 more answers
a faucet is leaking water at a speed of 5 drops per minute. If 1 ml is equivalent to 10 drops, how many liters of water will be
nikdorinn [45]

Answer: 0.72 litres of water is wasted in one day.

Explanation:

First you need to find out how many minutes are in a day. Do this by multiplying the number of minutes in an hour (60) by the number of hours in a day (24). 24 x 60 = 1440. If the faucet is dripping at 5 drops per minute, then multiply 5 by the number of minutes in a day (1440) to see how many drops drip in one day. 5 x 1440 = 7200. Now we need to figure out how many mL fo water that is. if 10 drops is 1 mL, then we need to divide the total number of drops (7200) by 10. 7200 divided by 10 is 720. That means 720 mL of water is dripping per day. Finally, we must convert mL to litres. There are 1000 mL in one litre, so divide 720 by 1000. The final answer is 0.72

6 0
2 years ago
A certain first order reaction has a half-life of 54. 3 s. How long will it take (in s) for the reactant concentration to decrea
Maksim231197 [3]

Answer:

82.4 s

Explanation:

Find the NUMBEr of half lives...then multiply by 54.3

2.27 = 6.5 (1/2)^n

log (2.27/6.5) / log (1/2) = n = 1.52 half lives

1.52 * 54.3 = 82.4 s

8 0
1 year ago
What compound is formed when 2,2-dimethyloxirane (2-methyl-1,2-epoxypropane) is treated with ethanol containing sulfuric acid
vladimir1956 [14]

Answer:

2-ethoxy-2-methylpropan-1-ol

Explanation:

On this reaction, we have an "<u>epoxide"</u> (2-methyl-1,2-epoxypropane). Additionally, we have <u>acid medium</u> (due to the sulfuric acid H_2SO_4). The acid medium will produce the <u>hydronium ion</u> (H^+). This ion would be attacked by the oxygen of the epoxide. Then a <u>carbocation</u> would be produced, in this case, the most stable carbocation is the <u>tertiary one</u>. Then an <u>ethanol</u> molecule acts as a nucleophile and will attack the carbocation. Finally, a <u>deprotonation </u>step takes place to produce <u>2-ethoxy-2-methylpropan-1-ol</u>.

See figure 1

I hope it helps!

3 0
3 years ago
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