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krek1111 [17]
4 years ago
5

C + H2O → CO + H2 What substance are we expected to solve for?

Chemistry
1 answer:
Bingel [31]4 years ago
3 0
Photosynthesis if not then goggle it lol
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To make lemonade Erica dissolved 30 g of sugar in a certain amount of water. By what amount is the mass of water likely to incre
Brrunno [24]

Answer:

D. 30 g

Explanation:

Conversion of mass ensures that though the sugar may appear gone the particles remain and will only add onto the original liquid

4 0
3 years ago
What is the primary cause of diffusion? 1.that some substances can dissolve in solvents 2.heat added to a substance 3.random int
shusha [124]
Diffusion : a process in which molecules intermingle as a result of  their kinetic energy of random motion
The primary cause of diffusion is : 3. Random internal motion of atoms and molecules

hope this helps
6 0
3 years ago
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In which location would you expect to find the greatest species diversity?!
7nadin3 [17]
The correct answer is D : United States

All of the other countries on the list have great species diversity, especially Cosa Rica due to it's closeness to the equator and therefore its tropical climate perfectly suitable for wildlife thrive.
But, the United States' territory covers the areas with the mild climate, forests, deserts, canyons and species-rich coastal regions as well as the Hawaii islands with unique species diversity and the Alaskan area with the arctic habitat.
7 0
4 years ago
A food chemist determines the concentration of acetic acid in a sample of apple vinegar by acid base titration. The density of t
Scilla [17]

Answer:

The concentration of acetic acid in the vinegar is 7,324 (%V/V)

Explanation:

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NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O

The moles required were:

1,024M×0,02500L = <em>0,02560 moles NaOH. </em>These moles are equivalent (By the titration equation) to moles of CH₃COOH. As molar mass of CH₃COOH is 60,052g/mol, the mass in these moles of CH₃COOH is:

0,02560 moles CH₃COOH×\frac{60,052g}{1mol}= <em>1,537g of CH₃COOH</em>

As density is 1,01g/mL:

1,537g CH₃COOH×\frac{1mL}{1,01g}= <em>1,522mL of CH₃COOH</em>

<em />

As volume of vinegar in the sample is 20,78mL, the concentration of acetic acid in the vinegar is:

\frac{1,522mLCH_{3}COOH}{20,78mL}×100= <em>7,324 (%V/V)</em>

<em />

I hope it helps!

3 0
3 years ago
How many grams are in8.2'10^22 molecules of N2i6​
maks197457 [2]

Explanation:

Hope the picture with the working out helps :)

4 0
3 years ago
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