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MA_775_DIABLO [31]
3 years ago
8

Which of the following chemical formulas contains the most molecules?

Chemistry
1 answer:
maw [93]3 years ago
4 0
C. 2Fe2O3 would be the correct answer!
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Label the parts of the respiratory system.
Evgesh-ka [11]

Answer:

1. Nose

2. Mouth

3. Larynx

4. Lung

5. RIght Bronchi

6. Diaphragm

7. Pharynx

8. Trachea

9. Left Bronchi

10. Bronchioles

11. Avoli

Explanation:

8 0
3 years ago
What is not within the scope of chemistry
ankoles [38]

hello!

your answer will be

The origin of the matter does not usually fall into chemistry

have a goed day

5 0
3 years ago
How did the development of the earliest idea about atoms differ from the later work of scientists?
Ket [755]

Answer:

C

Explanation:

The early ideas of the atom states that the indivisible object is hollow or is a solid object with nothing inside. The later discoveries or works of the scientists states that inside the atoms are the subatomic particles which are the electrons, protons, and neutrons.

6 0
3 years ago
0.0009547863= x^-1.644
Andrej [43]

Answer: 68.71317831

Explanation:

5 0
3 years ago
The standard enthalpy change for the following reaction is 232 kJ at 298 K. 2 H2CO(g) 2 C(s,graphite) + 2 H2(g) + O2(g) ΔH° = 23
Georgia [21]

Answer:  The standard enthalpy change for this reaction is -116 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

2H_2CO(g)\rightarrow 2C(s, graphite)+2H_2(g)+O_2(g)

\Delta H^0=232KJ

Now we have to determine the value of \Delta H for the following reaction i.e,

)C(s, graphite)+H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2CO(g) \Delta H^0'=?

According to the Hess’s law, if we reverse the reaction then the \Delta H will change its sign and if we half the reaction, then the

So, the value \Delta H^0' for the reaction will be:

\Delta H^0'=\frac{(-232kJ/mole)}{2}=-116kJ

Hence, the standard enthalpy change for this reaction is -116 kJ

7 0
4 years ago
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