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nasty-shy [4]
3 years ago
5

Write the formula for aluminum oxide.

Chemistry
2 answers:
exis [7]3 years ago
6 0

Answer:

Al₂O₃

Explanation:

-Dominant- [34]3 years ago
5 0

Answer: Al2O3

Explanation:The answer is Al2O3.

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A buffer is prepared by adding 18.0 g of sodium acetate (ch3coona to 510 ml of a 0.160 m acetic acid (ch3cooh solution. determin
Nutka1998 [239]
Given:

mass of sodium acetate = 18.0 grams
volume of acetic acid = 510 ml
concentration of acetic acid = 0.160 M

Solve for the ph of the buffer:

pH = pKa + log [salt]/[acid]

pKa of acetic acid = 4.76
M of sodium acetate = 82g/mol
pH = 4.76 + log [18g/82g/mol] / [0.160M*(510/1000)]
pH = 5.19


4 0
3 years ago
What is a molecular Solid
Iteru [2.4K]

Question

what is a molecular Solid

Answer:

A molecular solid is a type of solid in which molecules are held together by van der Waals forces rather than by ionic or covalent bonds.

Explanation:

A molecular solid is a solid consisting of discrete molecules. The cohesive forces that bind the molecules together are van der Waals forces, dipole-dipole interactions.

8 0
3 years ago
Could someone please help me with number 2 I am really confused
murzikaleks [220]
Physicam because the size or form is changing not what its composed of
7 0
3 years ago
Determine the heat of reaction (ΔHrxn) for the reaction of calcium carbonate (CaCO3) with HCl to produce CO2 by using heat of fo
andrey2020 [161]

Answer: The heat of reaction (ΔHrxn) for the reaction is -164.9kJ

Explanation:

The given balanced chemical reaction is,

CaCO_3(s)+2HCl(g)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(g)

To calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{CaCl_2}\times \Delta H_f^0_{(CaCl_2)}+n_{CO_2}\times \Delta H_f^0_{(CO_2)}+n_{H_2O}\times \Delta H_f^0_{(H_2O)}]-[n_{CaCO_3}\times \Delta H_f^0_{(CaCO_3)+n_{HCl}\times \Delta H_f^0_{(HCl)}]

where,

\Delta H^o_f_{(CaCO_3(s))}=-1206.9kJ/mol\\\Delta H^o_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H^o_f_{(CaCl_2(s))}=-877.1kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-285.8kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.51kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times -877.1)+(1\times -393.51)+(1\times -285.8)]-[(1\times -1206.9)+(2\times -92.30)]=-164.9kJ

Therefore the heat of reaction (ΔHrxn) for the reaction is -164.9kJ

6 0
3 years ago
4.702 x 10^-4 in standard form?
Julli [10]
The answer is .0004704. i hope that helped.
7 0
3 years ago
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