I need help with dis plz da one day says during

When plant cells lengthen, it is called _____. stretching elongation lengthening girth

motikmotik

Answer:

The correct answer would be elongation.

Cell elongation is defined as the lengthening of a cell during differentiation of a cell. It takes place during growth of an organism or during movement in mature plants.

In plants, it is primarily regulated by light and plant hormones like auxin.

Auxin modifies the structure of the cell wall which helps the cell to elongate.

8 0

3 years ago

How does a scientist come up with a theory?

Tatiana [17]

Answer:

A scientific theory is an explanation of an aspect of the natural world that can be repeatedly tested and verified in accordance with the scientific method

Explanation:

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3 years ago

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In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,2

Alisiya [41]

Answer:

Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

$r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}$

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

$r = \frac{1500 - 750}{1995 - 1985} = 750/10 = 75$

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

area = 250 ha

Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

$r = \frac{D(1995) - D(1885)}{1995 - 1985} = \frac{6 pines/ha - 3pines/ha}{10} = 0.3 pines/ha$

So, on average, each year the number of pines per hectare increases by 0.3

7 0

3 years ago

On what basis are enzymes classified and named?

Zielflug [23.3K]

Enzymes are classified and named according to the<u> types of reactions they catalyze.</u>

Explanation:

According to the International Union of Biochemistry and Molecular Biology nomenclature of enzyme classification, enzymes are classified depending upon the reactions they catalyze and how the reaction transforms the substrate and forms new products.

Based on the reactions:

Addition reaction (removal of a water molecule): hydrases or hydrolases like esterases, nucleases etc

Electron transfer reaction: Oxidases and dehydrogenases

Radical transfer reaction: Transglycosidases, transaminases, etc

Splitting or C-C bond formation: Desmolases

Structural or geometrical change: Isomerases

Hydrolysis of phosphate bonds to join molecules: Ligases

Based on the general principle of recommendations, enzymes are suffixed with –ase depending upon the catalytic reaction and substrate.

8 0

3 years ago

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Please Help asp

solmaris [256]

Answers:

1. Facilitated diffusion: the process by which some molecules that are not able to pass directly through a cell membrane are able to enter the cell with the aid of transport proteins.

2. Osmosis: the diffusion of water molecules through a selectively permeable membrane.

3. Diffusion: the spreading out of molecules across a cell membrane until to they are equally concentrated.

Step-by-step explanation:

Diffusion is the spontaneous movement of molecules across a membrane from an area of high concentration to one of low concentration gradient.

Osmosis is the diffusion of water molecules across a semipermeable membrane from an area of low solute concentration to one of high solute concentration.

Facilitated transport occurs when molecules cannot diffuse directly through a cell membrane but can diffuse down a concentration gradient through transport channels in the membrane.

8 0

3 years ago