Answer:
b. the action is not allowed.
Explanation:
Traffic signs are established rules and regulations designed to direct and guide commuters and other road users.
A red circle and diagonal slash on a sign simply means that the action is not allowed.
A hortatory technique is focused on encouraging, exhorting and urging people to do that which is right, acceptable and worthy of emulation by others.
For example, commuters and road users are being urged not to litter the highway with thrash, waste, or dirt, in order to protect the planet from environmental degradation and pollution. This would help in conserving and mitigating risks posing as a threat to our dear planet and habitat.
Hence, a hortatory technique in policy implementation and enactment is primarily aimed at appealing to the sense and conscience of individuals, to engage in socially responsible acts.
Answer:
The correct option is A
Explanation:
In project management, earliest finish time for activity A refers to the earliest start time for succeeding activities such as B and C to start.
Assume that activities A and B comes before C, the earliest finish time for C can be arrived at by computing the earliest start-finish (critical path) of the activity with the largest EF.
That is, if two activities (A and B) come before activity C, one can estimate how long it's going to take to complete activity C if ones knows how long activity B will take (being the activity with the largest earliest finish time).
Cheers!
What if u can explain half question I can answer
Answer:
I think
BASIC programming language
The only way without a while loop and no method I can think of is use switch with every possible variation of the four digit binary which is 15.
Here is the starter code:
import java.util.Scanner;
public class MyClass {
public static void main(String args[]) {
Scanner sc = new Scanner(System.in);
int digit = sc.nextInt();
switch(digit) {
case 0000:
System.out.println("0");
break;
case 0001:
System.out.println("1");
break;
case 0010:
System.out.println("2");
break;
case 0011:
System.out.println("3");
break;
case 0100:
System.out.println("4");
break;
… (fill in other cases)
}
}
}
Use this link: https://www.electronics-tutorials.ws/binary/bin_3.html
There might be a better way, but without loops or methods this is all I got.
