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Flauer [41]
3 years ago
10

How do I make this as simplest form qns: 5 2/3 + 3 1/10 pls answerthe prod. is 8 23/30 ​

Mathematics
1 answer:
umka2103 [35]3 years ago
3 0

Answer:

That is the final product

Step-by-step explanation:

According to all sites I used, they all said that was in the simplest form and cannot be simplified lower than that.

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What’s does 2+2 evaluation to
topjm [15]

Answer:4


Step-by-step explanation:

2+2 = 4

Adding 2 in 2 gives us 4.

4 0
3 years ago
When servicing a heating boiler and radiators, a plumer knows that the time he will take is given by the formula
Allushta [10]

Answer:

£110

Step-by-step explanation:

We know how much time it takes for a boiler and a radiator, and we need to know how much it will cost for 1 boiler and 4 radiators. We have an initial cost of £30, and since hes doing a boiler - which we know takes an hour - we can already add £20 for a start of £50.

Now, there are 4 radiators, that take 45 minutes each. We need to use this equation:

(45*4)/60

We divide by 60 because there are 60 minutes in an hour, and he charges by hour. So:

180/60=3

Now, to find out how much to charge, we need to figure out how much to add to the £50. Since it's £20 an hour, and it takes 3 hours to do the 4 radiators, we need to multiply:

3*20=60

Now we add our totals for a grand total of...

50+60=110

6 0
3 years ago
Which of these numbers is the greatest? No links
Ahat [919]

Answer:

c. 1.2 * 10^4

5 0
3 years ago
Read 2 more answers
A quadrilateral has congruent side lengths. 2 opposite angles have measures of 100 degrees. The other 2 opposite angles have mea
Burka [1]

Answer:

x = 14.

Step-by-step explanation:

The other 2 opposite angle are both equal to 70 degrees.

So 5x = 70

x = 70/5

= 14 degrees.

6 0
3 years ago
Read 2 more answers
What are the coordinates of the inflection point on the graph of y=(x+1)arctanx
Dennis_Churaev [7]

Inflection point is the point where the second derivative of a graph is zero.

y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2

Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2

Therefore, E(1, pi/2).


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

5 0
3 years ago
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