Answer:
Angle x is 64 degrees. Angle y is 128.
Step-by-step explanation:
To find angle x:
In an isosceles triangle, the base angles are always congruent (equal). Since we know that one of the base angles is 64, and x is also a base angle, x is 64 degrees as well.
To find angle y:
Again, in an isosceles triangle, the base angles are always congruent. Since we know that one of the base angles is 26, we know that the other base angle is also 26. Then, to find the last angle (y), you use the triangle angle sum theorem which states that all angles in a triangle add up to 180. To figure out angle y, you do 180-26-26 to get 128. So angle y is 128 degrees.
24:15 would be the simplified version, if that's what you meant.
In centre is the centre of a circle that is inscribed in a triangle, called the incircle, i.e. circle is tangent to all three sides AND located inside the triangle. An incircle is roughly sketched in the accompanying diagram.
Since all radii of an incircle are equal, we have
4x-1=6x-5
Solving for x,
6x-4x=5-1
x=2
consequently, distance from incentre to each side of the triangle is
4(2)-1=7
check 6x-5=6(2)-5=7... checks.
Answers:
The value of x = 2
The distance from incentre to side of triangle is 7
Answer:
Horizontal line: y=-5
Vertical line: x = 4
Step-by-step explanation:
As we have to determine the equations for the horizontal and vertical lines passing through the point (4, -5).
- To determine the equation for the horizontal line passing through the point (4, -5), we must observe that the horizontal line will always have the same y-value regardless of the x-value.
Therefore, the equation of the horizontal line passing through the point (4, -5) will be: y=-5
- To determine the equation for the vertical line passing through the point (4, -5), we must observe that the vertical line will always have the same x-value regardless of the y-value.
Therefore, the equation of the vertical line passing through the point (4, -5) will be: x=4
Hence:
Horizontal line: y=-5
Vertical line: x = 4
