Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
Answer:
A) 5x + 2y = 22
B) -2x + 6y = 3 We'll multiply A) by -3
A) -15x -6y = -66 Then we'll add B)
B) -2x + 6y = 3
-17x = -63
x = 3.7058823529
y = 1.7352941178
Step-by-step explanation:
Answer:
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Step-by-step explanation:
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Answer:
4^2+2^2, 5^2, 6^2-6
Step-by-step explanation:
4 to the power of 2 is 16 and 2 to the power of 2 is 4. 16+4 is 20.
5 to the power of 2 is 25 which is greater than 20.
6 to the power of 2 is 36 minus 6 is 30 which is greater than 25 and 20.
