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VashaNatasha [74]
3 years ago
12

PLEASE HELP WITH THIS QUESTION

Mathematics
1 answer:
marishachu [46]3 years ago
5 0

Answer:

which question can I help you

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Me ajudem por favor<br><br><br><br><br> PS: Explicar resposta
PolarNik [594]

Answer:

B

Step-by-step explanation:

√16/25 = 4/5 = 0.8-> (4/5 x 4/5 = 16/25)

(2/5)^3 = 8/125  = 0.064

-(-0.3)^3 = 0.027 (an odd exponent mantains the same sign of the number and minus x minus = +)

-√169 = -13

-13 is a negative number so it is surely the smallest

2 is minor than 6 so we have that 0.027 is minor than 0.064

8 is major than 0, so 0.8 is the greatest number

we have

-√169 ; -(-0.3)^3 ; (2/5)^3 ; √16/25

4 0
3 years ago
Heather opens a bank account with $125. Each week, starting the following week, she deposits $25 into her account.
vichka [17]
The equation is y=25n+125 I think
3 0
4 years ago
Read 2 more answers
At a used book sale, 5 books cost $15. What is the cost per book?
Arte-miy333 [17]

Answer:

$3/book

Step-by-step explanation:

cost per book means divide the price of all the books by the number of books

$15/(5 books) = $3/book

4 0
3 years ago
(3.14) please help me as soon as possible ....
Luden [163]
37.68 is the correct answer
6 0
3 years ago
Read 2 more answers
Let f be a differentiable function such that f(1)=π and f'(x)=√x^3+6. what is the value of f(5)?
natali 33 [55]

The value of f(5) is 49.1

Step-by-step explanation:

To find f(x) from f'(x) use the integration

f(x) = ∫ f'(x)

1. Find The integration of f'(x) with the constant term

2. Substitute x by 1 and f(x) by π to find the constant term

3. Write the differential function f(x) and substitute x by 5 to find f(5)

∵ f'(x) = \sqrt{x^{3}} + 6

- Change the root to fraction power

∵ \sqrt{x^{3}} = x^{\frac{3}{2}}

∴ f'(x) = x^{\frac{3}{2}} + 6

∴ f(x) = ∫ x^{\frac{3}{2}} + 6

- In integration add the power by 1 and divide the coefficient by the

 new power and insert x with the constant term

∴ f(x) = \frac{x^{\frac{5}{2}}}{\frac{5}{2}} + 6x + c

- c is the constant of integration

∵ \frac{x^{\frac{5}{2}}}{\frac{5}{2}}=\frac{2}{5}x^{\frac{5}{2}}

∴ f(x) = \frac{2}{5} x^{\frac{5}{2}} + 6x + c

- To find c substitute x by 1 and f(x) by π

∴ π = \frac{2}{5} (1)^{\frac{5}{2}} + 6(1) + c

∴ π = \frac{2}{5} + 6 + c

∴ π = 6.4 + c

- Subtract 6.4 from both sides

∴ c = - 3.2584

∴ f(x) = \frac{2}{5} x^{\frac{5}{2}} + 6x - 3.2584

To find f(5) Substitute x by 5

∵ x = 5

∴ f(5) = \frac{2}{5} (5)^{\frac{5}{2}} + 6(5) - 3.2584

∴ f(5) = 49.1

The value of f(5) is 49.1

Learn more:

You can learn more about differentiation in brainly.com/question/4279146

#LearnwithBrainly

4 0
3 years ago
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