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Over [174]
3 years ago
13

What is the formula for axis of symitry and vertex of a porabala?

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
5 0
Axis of symmetry is x=-b/2a

& the coordinate of the vertex (-b/2a, b^2/4a)
blsea [12.9K]3 years ago
3 0
Axis of Symmetry: x = -b/2a
Vertex: y = Ax² + By + c  
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Find the area of the following figure.<br><br> 14.0 cm2<br> 10.5 cm2<br> 28.1cm2<br> 17.6 cm2
Levart [38]
First option: 14.0 cm^2

Area of semicircle + area of triangle
1/2(pi)(r^2) + 1/2(b)(h)
1/2(3.14)(1.5^2) + 1/2(3)(7)
3.53+ 10.5
14.03 cm^2
7 0
2 years ago
1. Simplify. (343)1/3
elena-s [515]

1) 343/32 or 10.71875 or 10 23/32
2)-8
3)7
8 0
3 years ago
The point (-3/5,y) in the third quadrant corresponds to angle θ on the unit circle.
romanna [79]
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate

hypotenuse = 1 (because it is the radius of the unit circle)

sec (theta) = 1 / (-3/5) = - 5/3

cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate

cot (theta) = -3/5 / y

y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5

Third quadrant => y = -4/5

=> cot (theta) = (-3/5) / (-4/5) = 3/4
7 0
3 years ago
Lucia has $600 in her checking account. She wants to spend part of this money on a computer. She wants to have exactly $250 left
sesenic [268]

Answer:

t = 350

Step-by-step explanation:

subtract 250 from each side, and then you'll have t = 350

3 0
3 years ago
Read 2 more answers
From his eye, which stands 1.59 meters above the ground, Francisco measures the
viva [34]

The height of the skyscraper to the nearest tenth is 234. 95 meters.

<h3>How to determine the height</h3>

From the information given, we have:

  • angle of elevation = 32°
  • length of the base, adjacent side = 376 meters
  • height of the skyscraper, opposite side = x meters

To determine the height of the elevator, let's use the tangent identity

We have that;

tan θ = opposite/ adjacent

The value of the opposite side is 'x' which is the height of the skyscraper and the value of the adjacent side is 376 meters which is the length of the base of the skyscraper

Now, substitute the values, we have;

tan 32 = x/ 376

cross multiply

x = tan 32 × 376

x = 0. 6249 × 376

x = 234. 95 meters

We know that the 'x' represents the opposite side and thus the height of the skyscraper

Thus, the height of the skyscraper to the nearest tenth is 234. 95 meters.

Learn more about angle of elevation here:

brainly.com/question/19594654

#SPJ1

7 0
2 years ago
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