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2 years ago

Can someone help me with my science it’s super hard :(

Chemistry

1 answer:

Lunna [17]2 years ago

5 0

Answer: here is a description of what they look like since I cannot see the diagram.

Mitochondria- wavy line

Ribosomes- little dots

Chromosome- X

Nucleus- Circle with bite taken out of it

Endoplasm- Bubble

Nuclear membrane- Outer layer/bubble

Golgi-wavy circle thing

Vacuole- Bigger circle (but not nucleus)

Cytoplasm- its the jelly on the inside

Cell wall- only in plant cells, looks like a box

Cell membrane- The outmost part of the animal cell, the barrier.

I sure hope this helps!!!

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What is the volume of 3.00 M sulfuric aid that contain 9.809 g of H2SO4 (98.09g/mol)

Slav-nsk [51]

Given :

Molarity of sulfuric acid solution is 3.0 M.

Amount of sulfuric acid present in solution is 9.809 g.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

$Molarity = \dfrac{number \ of \ moles \times 1000}{Volume\ ( ml )}\\\\M = \dfrac{w \times 1000}{M.M \times V}\\\\3 = \dfrac{9.809\times 1000}{98.09 \times V}\\\\V = \dfrac{1000}{10\times 3}\ ml\\\\V = 33.33 \ ml$

Therefore, volume required is 33.33 ml .

5 0

3 years ago

PLEASE HELP

Marysya12 [62]

Answer:

Military

Explanation:

I may be wrong but military seems most likely

6 0

2 years ago

Read 2 more answers

A field worker is exposed to a xylene for a duration of 8 weeks at 40 hrs/wk. The concentration of xylene in the workplace is 40

Andrej [43]

Answer:

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

Explanation:

Number of hours worker exposed to xylene = $40 hr/week\times 8 week = 320 hours$

The concentration of xylene in the workplace = $40 \mu g/m^3$

The worker is inhaling air at a rate of $0.9 m^3/hr$ .

Amount xylene inhaled by worker in an hour :

= $40\mu g/m^3\times 0.9 m^3/hr=36 \mu g/hr$

Amount xylene inhaled by worker in 320 hours:

$36 \mu g/hr\times 320 hr=11,520 \mu g=11,520\times 0.001 mg=11.520 mg$

1 μg = 0.001 mg

Amount xylene inhaled by worker in 320 hours = 11.520 mg

1 day = 24 hours

Amount xylene inhaled by worker in 1 day:

$\frac{24}{320}\times 11.520 mg=0.864 mg$

Assuming 70 kg body mass, the chronic daily intake of xylene :

$\frac{0.864 mg/day}{70 kg}=0.01234 mg/ kg day\approx 0.012 mg/ kg day$

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

5 0

2 years ago

Y'all what about this one

Virty [35]

Answer:

A=8, B=7,C=N

D=26, E=30, F =Fe

4 0

3 years ago

For an insoluble compound, how might you prevent formation of the precipitate

anastassius [24]

<span>protect it by covering it by lyophilic sol.</span>

8 0

2 years ago