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const2013 [10]
3 years ago
7

In Rutherford's Gold foil experiment, were the alpha particles directed to different areas of the gold foil or only the same spo

t? If the same spot, how did the particles get deflected in different directions sometimes and go through most of the time
Chemistry
1 answer:
MrRissso [65]3 years ago
8 0

Answer:

See explanation

Explanation:

In the Rutherford experiment, alpha particles were directed at the same spot on a thin gold foil.

As the alpha particles hit the foil, most of the alpha particles went through the foil. In Rutherford's interpretation, most of the particles went through because the atom consisted largely of empty space.

However, some of the alpha particles were deflected through large angles, in Rutherford's interpretation, the deflected alpha particles had hit the dense positive core of the atom which he called the nucleus.

This accounted for their scattering through large angles throughout the foil in all directions.

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Base your answer on the information below. The hydrocarbon 2-methylpropane reacts with iodine as represented by the balanced equ
Kryger [21]

Answer:

See explanation

Explanation:

The boiling point of a substance is affected by the nature of bonding in the molecule as well as the nature of intermolecular forces between molecules of the substance.

2-methylpropane has only pure covalent and nonpolar C-C and C-H bonds. As a result of this, the molecule is nonpolar and the only intermolecular forces present are weak dispersion forces. Therefore, 2-methylpropane has a very low boiling point.

As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than  2-methylpropane.

3 0
2 years ago
In beta decay, what is emitted? A. an electron B. a helium-4 atom C. a neutron D. a photon E. a radionucleus
myrzilka [38]

Answer: A. an electron

<u>Beta particles are electrons or positrons (electrons with positive electric charge or antielectrons).</u> Beta decay is a type of radioactive decay in which a beta ray is emitted from an atomic nucleus.

<u>Beta decay occurs when, in an unstable nucleus with too many protons or too many neutrons, one of the protons or neutrons transforms into the other.</u> In beta minus decay, a neutron is broken down into a proton, an electron, and an antineutrino (the neutrino antiparticle, meaning it has an opposite charge to the neutrino). In beta decay plus, a prototype breaks down into a neutron, a positron and a neutrino.

4 0
2 years ago
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vampirchik [111]
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5 0
2 years ago
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Why are nanowhiskers used to repel stains on fabrics??
WINSTONCH [101]

Nanowhiskers or cellulose nanofibers are nano-structured cellulose produced by bacteria. They have relatively high crystallinity and ability to form a dense network held together by inter-fibrillar bonds that has the tendency to act as a barrier through their film-forming properties to which they can repel stains on fabric.

 

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7 0
3 years ago
WILL GIVE BRAINLIEST <br> Explain why HS2 has a bent geometry, while BeH2 has a linear geometry.
Natali5045456 [20]

Answer:

H2S has a bent geometry, while BeH2 has a linear geometry because: presence of lone pair in H2S

Absence of Lone pair in BeH2

Explanation:

<u>Structure of H2S :</u>

Atomic number of S = 16 = 1s(2 )2s(2) 2p(6) <u>3s(2 )3p(4)</u>

Outer most shell has 6 electron

Valence electron (Involved in bonding) = 6

Out of these  6 electrons ,

2 electrons are formed in bonding with Hydrogen

Rest 4  are non- bonding  and present as lone - pair

H2S exist - sp3 hybridisation

There are 2-Lone pair on S in H2S (look at the image attached)

<u>Structure of H2S :</u>

Atomic number of Be = 4 = 1s(2 ) 2s(2)

Valence electron (Involved in bonding) = 2

These 2- electron  are involved in bonding with two Hydrogen and form liner shape.*Form sp - hybridized

Hence shape is linear because it has non - lone pair.

VSEPR : <u><em>According to this theory lone pair causes repulsion to the bond and cause unstability in the molecule.</em></u>

<u><em>Hence the bonds shifts away from lone pairs . This is why H-S bonds in H2S  shifts way from lone pair</em></u>

5 0
3 years ago
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