The equation of a circle is (x-h)^2 + (y-k)^2 = r^2. Where "x" and "y" are variables, "h" and "k" are the coordinates of the center of the circle, and "r" is the length of the radius. It is given that the center of the circle is (-27, 120). So, h= -27 and k= 120. If the circle passes through the origin, we can assume that the origin is on the circle. Since a circle's radius is constant no matter where it is drawn/is, we can find the radius of the circle by finding the distance between the circle's center (-27, 120) and the origin, (0, 0). The distance formula is: d= √((x[2]-x[1])^2-(y[2]-y[1])^2). If the coordinates of the center of the circle are (x[2}, y[2]), then x[2]= -27 and y[2]= 120. Then, the origin is the (x[1], y[1]). So, x[1] = 0 and y[1] = 0. Plugging the numbers in we get: √((-27-0)^2-(120-0)^2). This gives us √(729+14400) = 123. So since the distance between the center of the circle and a point on the circle is 123 (units), then the radius has a value of 123.
Plugging all the numbers into the equation of a circle, we get: (x-(-27))^2+(y-120)^2=123^2.
B, the first differences are not the same , that proves it is not linear. The second set of differences are the same this shows it is a quadratic function.
We have to find the values of m and n. We know that the value of n is 5 times as much as the value of m : n = 5 m. Also n is 36 more than the value of m : n = m + 36. This is a system of equations. Of we substitute n = 5 m into the second equation: 5 m = m + 36; 5 m - m = 36; 4 m = 36; m = 36 : 4; m = 9. Finally: n = 5 * 9 ; n = 45. Answer: The values are n = 45 and m = 9.
Yes jk and kl are the same length because if you count the amount of units they reach from the first point to the last they both are 3 squared units/units how ever you want to call it.
