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Veseljchak [2.6K]
3 years ago
13

PLS help 85% of 2500m

Mathematics
1 answer:
pishuonlain [190]3 years ago
3 0

Answer:

2125m or 2km or 125m

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

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Answer:

Step-by-step explanation:

Given function is

(a)F(x)=\left ( x^{3}+5\right )^{0.25}-15e^{x^{3}}

F^{'}\left ( x\right )=0.25\left ( x^{3}+5\right )^{-0.75}\frac{\mathrm{d} x^{3}}{\mathrm{d} x}-15e^{x^{3}}\frac{\mathrm{d} x^{3}}{\mathrm{d} x}

F^{'}\left ( x\right )=0.25\left ( x^{3}+5\right )^{-0.75}\times 3x^{2}-15e^{x^{3}}\times \left ( 3x^{2}\right )

(b)F(x)=\frac{\left ( x-3\right )^2\left ( x-5\right )}{\left ( x-4\right )^2\left ( x^{2}+3\right )^5}

F^{'}\left ( x\right )=\frac{\left [ 2\left ( x-3\right )\right \left ( x-5\right )+\left ( x-3\right )^2]\left [ \left ( x-4\right )^2\left ( x^2+3\right )^5\right ]-\left [ 2\left ( x-4\right )^{3}\left ( x^2+3\right )^5+5\left ( x^2+3\right )^4\left ( 2x\right )\left ( x-4\right )^2\right ]\left [ \left ( x-3\right )^2\left ( x-5\right )\right ]}{\left [\left ( x-4\right )^2\left ( x^2+3\right )^5\right ]^2}

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