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blagie [28]
2 years ago
14

Cot2a+tan2a/cot2a-tan2a=sec4a

Mathematics
1 answer:
mylen [45]2 years ago
7 0

Answer:

okay bilis namann mag bago pagibig mo sinta daig mo isatisat mata

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Y = −3x <br> x + y = −4<br> Solution system
Verizon [17]

Answer:

Step-by-step explanation:

Y = - 3x. Equation 1

x + y = - 4 equation 2

Putting value of y

x + (-3x) = - 4

x - 3x = - 4

-2x = - 4

x = - 4/-2 = 2

Putting value of x in the equation 1

Y = - 3(2)

Y = - 6

7 0
3 years ago
Please answer correctly, if you don't know it - please just pass by. ​
Kazeer [188]

Answer: 7.50x500...try that and that’s your answer

Step-by-step explanation:

5 0
3 years ago
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Which set of ordered pairs can be used to graph y=x−2. <br><br> Will give you brainliest.
Ann [662]

Answer:

y =-2 x=0

Step-by-step explanation:

put any number on x to find y

4 0
3 years ago
Travelers who fail to cancel their hotel reservations when they have no intention of showing up are commonly referred to as no-s
notsponge [240]

Answer:

a) 0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) 0 is the most likely value for X.

Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

No-show rate of 10%.

This means that p = 0.1

Four travelers who have made hotel reservations in this study.

This means that n = 4

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486

P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036

P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001

P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561

P(X = 1) = C_{4,1}.(0.1)^{1}.(0.9)^{3} = 0.2916

P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486

P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036

P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001

X = 0 has the highest probability, which means that 0 is the most likely value for X.

7 0
3 years ago
7 is subtracted from 7 times a number
PolarNik [594]

Answer:

(7x) - 7

Hope this helps!

8 0
3 years ago
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