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3 years ago

10

A credit card company charges 18% simple interest for overdue accounts. How much interest will Kristen owe three months from now

on a current balance of $1500?

1 answer:

Ber [7]3 years ago

4 0

Answer: The amount that Kristen would owe three months from now is $67.5

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents interest paid on the loan.

P represents the principal or the current balance.

R represents interest rate

T represents the duration for which the account is overdue in years.

From the information given,

P = 1500

R = 18%

T = 3 months = 3/12 = 0.25 year

I = (1500 × 18 × 0.25)/100 = $67.5

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For f (x) = 3x +1 and g(x) = x2 - 6, find (f 3)(x)

Sunny_sXe [5.5K]

Answer:

10

Step-by-step explanation:

f(x) = 3x + 1

f(3)= 3 * 3 + 1 + 10

5 0

2 years ago

I need help . Plz help me

Gekata [30.6K]

The mean is the same thing as the average. To find the average, add all the numbers up (aka find the sum of the numbers) and divide by how many numbers there is:
$average = \frac{sum \: of \: numbers}{\# \: of \: numbers}$

So the sum of your numbers is: -6 + 2 + 5 + -7 + -11 + -6 = -23. And there are 6 numbers total.
That means average = $\frac{-23}{6} = -3.833333$ ≈ -3.8

Your final answer is -3.8

5 0

3 years ago

A garden table and a bench cost $910 combined. The garden table costs $60 more than the bench. What is the cost of the

EastWind [94]

Answer:

You could subtract 910 from 60 which would give you 850 and that would be your answer.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye

Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let $\rho(x,y)$ be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

$m=\int\limits \int\limits_D \rho(x,y) \, dA$ .

From the question, the given density function is $\rho (x,y)=xye^{x+y}$ .

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

$I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx$ .

Since D is a rectangular region, we can apply Fubini's Theorem to get:

$I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx$ .

Let the inner integral be: $I_0=\int\limits^1_0xye^{x+y}dy$ , then

$I=\int\limits^1_0(I_0)dx$ .

The inner integral is evaluated using integration by parts.

Let $u=xy$ , the partial derivative of u wrt y is

$\implies du=xdy$

and

$dv=\int\limits e^{x+y} dy$ , integrating wrt y, we obtain

$v=\int\limits e^{x+y}$

Recall the integration by parts formula: $\int\limits udv=uv- \int\limits vdu$

This implies that:

$\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy$

$\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}$

$I_0=\int\limits^1_0 xye^{x+y}dy$

We substitute the limits of integration and evaluate to get:

$I_0=xe^x$

This implies that:

$I=\int\limits^1_0(xe^x)dx$ .

Or

$I=\int\limits^1_0xe^xdx$ .

We again apply integration by parts formula to get:

$\int\limits xe^xdx=e^x(x-1)$ .

$I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(-1)=1$ .

No unit is given, therefore the mass of the lamina is 1.

3 0

3 years ago

suppose that a number written as a decimal has an infinite number of non- repeating digits after the decimal point. What is this

faltersainse [42]

Answer: Irrational number

If the decimal digits repeat forever, then the repeating decimal is considered rational.

For instance, 2/99 = 0.020202020202... where the "02" repeats forever

If we don't have such a pattern, then we cannot write the decimal as a fraction of two integers and the number is not rational. So it is irrational.

8 0

3 years ago