Answer:
Along period electronegativity and ionization energy increases.
Along group electronegativity and ionization energy decreases.
Explanation:
Along period:
As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. Thus the attraction of the atoms for valance electrons increases. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required, and electronegativity also increases.
Along group:
As we move from top to bottom in periodic table the atomic sizes increases.The electrons are added in next energy level in every next element. Thus the valance electrons farther away from the nucleus and hold of nucleus becomes weaker, because of weak nuclear attraction atomic radii increases and electronegativity and ionization energy decreases.
Answer:
See explanation
Explanation:
If we take two nonmetals with little or no electronegativity difference between them, the shared electrons are not attracted greatly towards any of the bonding atoms. In other words, the shared electrons remain equidistant between the nuclei of the two bonding atoms.
The bond is nonpolar since polarity is introduced into covalent bonds by a significant difference in electronegativity of the bonding atoms.
Answer: I think its 32 I'm not sure
Explanation:
Answer:
[H⁺] = 0.00013 M
[OH⁻] = 7.7 × 10⁻¹¹ M
Explanation:
Step 1: Calculate the concentration of H⁺ ions
HCl is a strong acid that dissociates according to the following equation.
HCl ⇒ H⁺ + Cl⁻
The molar ratio of HCl to H⁺ is 1:1. The concentration of H⁺ is 1/1 × 0.00013 M = 0.00013 M.
Step 2: Calculate the concentration of OH⁻ ions
We will use the ionic product of water equation.
Kw = 10⁻¹⁴ = [H⁺] × [OH⁻]
[OH⁻] = 10⁻¹⁴/[H⁺] = 10⁻¹⁴/0.00013 = 7.7 × 10⁻¹¹ M