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Ipatiy [6.2K]
3 years ago
9

If a given solution contains 3.55 mol of calcium hydroxide, and the solution as a molarity of 0.667 M, what is the volume of the

solution?​
Chemistry
1 answer:
Alexus [3.1K]3 years ago
8 0

Answer:

Volume in L = 5.3 L

Explanation:

Given data:

Number of moles of calcium hydroxide = 3.55 mol

Molarity of solution = 0.667 M

Volume of solution = ?

Solution:

Formula:

Molarity = number of moles / volume in L

By putting values,

0.667 M = 3.55 mol / volume in L

Volume in L = 3.55 mol / 0.667 M

Volume in L = 5.3 L

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Answer:The metal complex formed would have the following formula [Cr(NO₂)₆]³⁻. The complex has a net negative charge and hence it can only be isolated as a salt with a positive cation so the formed complex could be isolated as potassium salt. The formula for salt would be K₃[Cr(NO₂)₆].

Explanation:

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so our calculated oxidation state of Cr is +3 which matches with the provided in question.

As we can see that the overall metal complex has a net negative charge and hence and only positively charged  cations can form a salt with this metal complex and hence only potassium K⁺ ions can form salt with the metal complex.

since overall charge present on the metal complex is -3 so 3 K⁺ ion would be needed to neutralize it and hence the formula of the metal salt would be K₃[Cr(NO₂)₆].

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