Question

Help me please!! This is timed and I’m stuck

Answer 1

Let's solve

$\\ \sf\longmapsto 2x^2+7x-15=0$

$\\ \sf\longmapsto x=\dfrac{-7\pm\sqrt{7^2-4(2)(-15)}}{2(2)}$

$\\ \sf\longmapsto x=\dfrac{-7\pm\sqrt{169}}{4}$

$\\ \sf\longmapsto x=\dfrac{-7\pm13}{4}$

$\\ \sf\longmapsto x=\dfrac{-7+13}{4}\:or \:\dfrac{-7-13}{4}$

$\\ \sf\longmapsto x=\dfrac{6}{4}\:or\:\dfrac{-20}{4}$

$\\ \sf\longmapsto x=\dfrac{3}{2}\:or -5$

Subtract

$\\ \sf\longmapsto 3/2-(-5)=3/2+5=13/2$

Option B

Answer 2

Answer:

Option (B.)

Step-by-step explanation:

Answer in the picture.hu