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vodka [1.7K]
3 years ago
7

How does air and debris travel within a tornado?

Physics
1 answer:
lisov135 [29]3 years ago
3 0

Answer:

anywhere the tornado goes debri goes except for the more heavier pieces they just go in random places but the lighter pieces stay with the tornado until the tornado is gone or disinegrated

Explanation:

around and around

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There is no( ) in time between the action and the reaction
Lesechka [4]
There is no (gap) in time between the action and the reaction

hope that helps:)
4 0
4 years ago
Large bodies of water help to keep nearby climates from being too hot or too cold because they
Ludmilka [50]
Large bodies of water help to keep nearby climates from being too hot or too cold because they absorb heat in the summer and slowly release that heat in the winter.

So your answer is absorb
7 0
4 years ago
As the soviet russian soldiers approached the camp what were the prisoners forced to do
konstantin123 [22]
The prisoners were forced to hide under their beds or take cover as the Russians would have to fight their way into the camps. Hope this helps :)
3 0
4 years ago
A severe storm on January 10, 1992, caused a cargo ship near the Aleutian Islands to spill 29,000 rubber ducks and other bath to
Anna35 [415]
The distance that the rubber ducks traveled = 1600 miles.
The time taken to travel this distance = 10 months.

By definition, the approximate average speed of the ocean is
v = (1600 miles)/(10 months)

Note that
1 mile = 1609 m 
10 months = (10 months)*(30 days/month) *(24 hours/day)
                  = 7200 hours (approx.)
                  = 7200*3600 = 2.592 x 10⁷ s

Therefore
v = \frac{(1600 \, m)*(1609 \, \frac{m}{mi}) }{(10 \, months)*(2.592 \times 10^{7} \, \frac{s}{10 \, months}) } = 0.0993 \, \frac{m}{s}

Also,
v = \frac{1600 \, m}{7200 \, h} =0.222 \, \frac{mi}{h}

Answer:
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6 0
3 years ago
To test a slide at an amusement park, a block of wood with mass 3.00 kgkg is released at the top of the slide and slides down to
dem82 [27]

Answer:

511.1 J

Explanation:

We are given that

Mass of wood block=m=3 kg

Vertical distance,h=23 m

Horizontal distance =x=30 m

Distance traveled in downward direction y=40 m

Initial velocity,u=0

y=ut+\frac{1}{2} gt^2

Where g=9.8 m/s^2

40=0+\frac{1}{2}(9.8)t^2=4.9t^2

t^2=\frac{40}{4.9}

t=\sqrt{\frac{40}{4.9}}=2.86 s

x=v_x\times t

30=v_x(2.86)

v=v_x=\frac{30}{2.86}=10.49 m/s

By work energy theorem

Change in kinetic energy=Work done= mgh-W

\frac{1}{2}mv^2-\frac{1}{2}mu^2=3\times 9.8\times 23-W

\frac{1}{2}(3)(10.49)^2-0=676.2-W

W=676.2-\frac{1}{2}(3)(10.49)^2=511.1 J

Hence, the work done due to friction on the block as it slides down the ramp=511.1 J

6 0
3 years ago
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