Question

1. How long would the car in Sample Problem C take to come to a stop from its initial velocity of 20.0 m/s to the west? How far would the car move before stopping? Assume a constant acceleration. Aron1​

Answer 1

The time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.

What is the distance?

The length of the path traveled by the body is known as the distance covered by the body.

Distance is a 1-dimensional phenomenon. its unit is a meter(m). The distance can be found by the product of velocity and time.

The given data in the problem will be

u is the initial velocity =20m/sec

t is the time =?

d is the distance =?

From the Newtons second law;

$\rm F \triangle t = \triangle P \\\\ \triangle t = \frac{\triangle P }{F} \\\\ \triangle t = \frac{m(v_f-v_i)}{F} \\\\ \ \triangle t = \frac{2240 (0-20))}{8410} \\\\ \triangle t = 5.3 \ sec$

The distance travelled before the car stop is,

$\rm \triangle t = \frac{1}{2} (v_f+v_i)\traingle t \\\\ \traingle x = \frac{1}{2} (-20+0)5.3 \\\\\ \triangle x= -53.3 m \ west$

Hence,the time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.

To learn more about the distance, refer to the link;

brainly.com/question/989117

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