1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rainbow [258]
3 years ago
6

A severe storm on January 10, 1992, caused a cargo ship near the Aleutian Islands to spill 29,000 rubber ducks and other bath to

ys into the ocean. Ten months later hundreds of rubber ducks began to appear along the shoreline near Sitka, Alaska, roughly 1600 miles away.
What was the approximate average speed of the ocean current that carried the ducks to shore in m/s and in mi/h? (Rubber ducks from the same spill began to appear on the coast of Maine in July 2003.)
Physics
1 answer:
Anna35 [415]3 years ago
6 0
The distance that the rubber ducks traveled = 1600 miles.
The time taken to travel this distance = 10 months.

By definition, the approximate average speed of the ocean is
v = (1600 miles)/(10 months)

Note that
1 mile = 1609 m 
10 months = (10 months)*(30 days/month) *(24 hours/day)
                  = 7200 hours (approx.)
                  = 7200*3600 = 2.592 x 10⁷ s

Therefore
v = \frac{(1600 \, m)*(1609 \, \frac{m}{mi}) }{(10 \, months)*(2.592 \times 10^{7} \, \frac{s}{10 \, months}) } = 0.0993 \, \frac{m}{s}

Also,
v = \frac{1600 \, m}{7200 \, h} =0.222 \, \frac{mi}{h}

Answer:
The average velocity is approximately 0.1 m/s, or 0.222 m/h. 

You might be interested in
1. A 14-cm tall object is placed 26 cm from a converging lens that has a focal length of 13 cm.
AURORKA [14]

Answer:

a) Please find attached the required drawing of light passing through the lens

By the use of similar triangles;

The image distance from the lens = 26 cm

The height of the image = 14 cm

c) The image distance from the lens = 26 cm

The height of the image = 14 cm

Explanation:

Question;

a) Determine the image distance and the height of the image

b) Calculate the image position and height

The given parameters are;

The height of the object, h = 14 cm

The distance of the object from the mirror, u = 26 cm

The focal length of the mirror, f = 13 cm

The location of the object = 2 × The focal length

Therefore, given that the center of curvature ≈ 2 × The focal length, we have;

The location of the object ≈ The center of curvature of the lens

The diagram of the object, lens and image created with MS Visio is attached

From the diagram, it can be observed, using similar triangles, that the image distance from the lens = The object distance from the lens = 26 m

The height of the image = The height of the object - 14 cm

b) The lens equation is used for finding the image distance from the lens as follows;

\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}

Where;

v = The image distance from the lens

We get;

v = \dfrac{u \times f}{u - f}

Therefore;

v = \dfrac{26 \times 13}{26 - 13} = \dfrac{26 \times 13}{13} = 26

The distance of the image from the lens, v = 26 cm

The magnification, M =v/u

∴ M = 26/26 = 1, therefore, the object and the image are the same size

Therefore;

The height of the image = The height of the object = 14 cm.

5 0
2 years ago
What is the formula for calculating mechanical power​
Oksi-84 [34.3K]

Answer:

Because work can be defined as force time distance, we can also use the following equation

Solution

P=power (w or ft-lbf/s)

F=force (N or lbf)

D=distance (m or ft)

T=time (sec)

One horsepower is equivalent to 550 ft-lbf/s and 745.7 watts.

6 0
3 years ago
How many Gigameters in 1600 meters
USPshnik [31]
1.6e-6 gl on the rest of your physics its a killer for me too
6 0
3 years ago
Read 2 more answers
A series of pulses of amplitude 0.25 m are sent down a string that is attached to a post at one end. The pulses are reflected at
Klio2033 [76]

Answer:

0m

Explanation:

since the string is rigidly attached to the post, the reflected and incident pulses are of the same amplitude but different polarities. At the point where the two pulses meet, the amplitude will be the addition of that of the incident and the reflected pulses. i.e Amplitude= 0.25 + -0.25=0m

4 0
3 years ago
Two cars start from rest at a red stop light. when the light turns green, both cars accelerate forward. the blue car accelerates
irinina [24]
<span>19 m/s
   This is an exercise in ignoring unneeded data. We want to know how fast the blue car is going after 3.6 seconds. The acceleration is 5.2 m/s^2 for 4.5 seconds. Since 4.5 is greater than 3.6, we know the car was under constant acceleration of 5.2 m/s^2 for the entire 3.6 seconds. So we just need to multiply to get the answer. 3.6 s * 5.2 m/s^2 = 18.72 m/s
   Since we only have 2 significant figures in our data, we need to round to 2 significant digits, giving 19 m/s</span>
7 0
3 years ago
Other questions:
  • An astronaut having mass 320 kg with equipment included is attempting an untethered space walk. The astronaut is initially at re
    6·1 answer
  • A 7kg object is dropped on Earth,. Assuming it has not yet hit the ground, what is the velocity of the object after 2 seconds of
    7·2 answers
  • Which of the following would not make a good insulator
    13·1 answer
  • A. B. C. D.<br> -___________
    13·1 answer
  • A hard rubber ball on a string is being used as a pendulum. When you first look at the pendulum, the ball is being held to one s
    11·1 answer
  • if a 3.1g ring is heated using 10.0 calories, its temperatures rises 17.9C calculate the specific heat capacity of the ring
    10·1 answer
  • The centre of mass of a metre rule is at the 50cm mark. state what is meant by Centre of mass​
    5·1 answer
  • Your bike is too big if your can't touch the ground A.Knees B.Hands C.Feet​
    7·1 answer
  • Two factors affect the amount of thermal energy in an object, The amount of space between its particles and The amount of motion
    5·1 answer
  • A periodic wave has a wavelength of 0,50 m and a speed of 20 m/s, What is the wave frequency?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!