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OLga [1]
2 years ago
13

How many palindromes between 1000 and 9999 inclusive are divisible by 9?

Mathematics
1 answer:
Serhud [2]2 years ago
5 0

Palindromes are numbers that remain the same, when reversed.

There are 10 palindromes divisible by 9 between 1000 and 9999

To do this, we list the numbers divisible by 9 between 10 and 99.

The numbers are:

\mathbf{A = 09,\ 18,\ 27,\ 36,\ 45.\ 54,\ 63,\ 72,\ 81,\ 90,\ 99}

Flip these numbers

\mathbf{B =90,\ 81,\ 72,\ 63,\ 54.\ 45,\ 36,\ 27,\ 18,\ 09,\ 99}

Combine corresponding numbers

\mathbf{AB =0990,\ 1881,\ 2772,\ 3663,\ 4554,\5445,\ 6336,\ 7227,\ 8118,\ 9009,\ 9999}

Rewrite as:

\mathbf{AB =990,\ 1881,\ 2772,\ 3663,\ 4554,\5445,\ 6336,\ 7227,\ 8118,\ 9009,\ 9999}

990 is less than 1000.

So, we have:

\mathbf{AB =1881,\ 2772,\ 3663,\ 4554,\5445,\ 6336,\ 7227,\ 8118,\ 9009,\ 9999}

Count the numbers

\mathbf{n(AB) =10}

Hence, there are 10 palindromes divisible by 9 between 1000 and 9999

Read more about palindromes at:

brainly.com/question/14076732

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Step-by-step explanation:

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2 years ago
If θ=0rad at t=0s, what is the blade's angular position at t=20s
babunello [35]
The attached figure represents the relation between ω (rpm) and t (seconds)
To find the blade's angular position in radians ⇒ ω will be converted from (rpm) to (rad/s)
              ω = 250 (rpm) = 250 * (2π/60) = (25/3)π    rad/s
              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰  ω dt  
 
while ω is not fixed from (t = 0) to (t =20)
the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0  to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵  (0) dt   + ∫₅¹⁵  (25/3)π dt + ∫₁₅²⁰  (10/3)π dt
     
the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
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Which mean:
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3 0
3 years ago
Point C is on line segment \overline{BD} BD . Given CD=x,CD=x, BC=5x-5,BC=5x−5, and BD=2x+7,BD=2x+7, determine the numerical len
NARA [144]

Answer:

CD = 3

Step-by-step explanation:

Given

CD = x

BC = 5x - 5

BD = 2x + 7

Required

Determine CD

Since, C is a point on BD, the relationship between the given parameters is;

BD = BC + CD

Substitute the values of BD, BC and CD

2x + 7 = 5x - 5 + x

Collect Like Terms

2x - 5x - x = -5 - 7

-4x = -12

Divide both sides by -4

\frac{-4x}{-4} = \frac{-12}{-4}

x = 3

To determine the length of CD;

Substitute 3 for x in CD = x

Hence;

CD = 3

3 0
3 years ago
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