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Mrac [35]
3 years ago
7

Differentiate y = csc(x)cot(x).

Mathematics
1 answer:
Rudik [331]3 years ago
3 0

Answer:

look at photo

Step-by-step explanation:

substitute y = 0

determine the definded range

transform the expressions

multiply

swap sides

set the numerator equal to 0

solve

find the intersection

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2(log 18 - log 3) + = 2log 1/16
Semmy [17]
What do you need?

2log 3/8

= -0.85
4 0
3 years ago
How to write y-6=-5/2 (x+4)
coldgirl [10]

Answer:

In point slope form, this is y = (-5/2)x + 2.  In standard form, it's (5/2)x + y = 2.

Step-by-step explanation:

y-6=-5/2 (x+4) has already been written in point-slope form.  The slope of the line is -5/2 and the point on the line is (-4,6).

In slope-intercept form:  add 6 to both sides of the original equation, obtaining y = 6 - (5/2)(x + 4), or y = 2 - (5/2)x, or y = (-5/2)x + 2


8 0
3 years ago
Please help me out with this equation!<br> i will mark as brainliest
Natali [406]

Answer:  Choice D

y = -(x - 2)^2 + 7

===========================================================

Explanation:

The highest point is (2, 7) so this is the vertex.

In general, the vertex is (h, k). We can say that h = 2 and k = 7.

The vertex form

y = a(x-h)^2 + k

updates to

y = a(x-2)^2 + 7

----------------

Note that the graph goes through (0,3) which is the y intercept. Plug those x,y coordinates into the equation above to solve for 'a'

y = a(x-2)^2 + 7

3 = a(0-2)^2 + 7

3 = a(-2)^2 + 7

3 = a(4) + 7

3 = 4a + 7

4a+7 = 3

4a = 3-7

4a = -4

a = -4/4

a = -1

----------------

Therefore, we have

y = a(x-2)^2 + 7

update to

y = -1(x-2)^2 + 7

which is the same as

y = -(x - 2)^2 + 7

and that's why the answer is choice D

4 0
3 years ago
Read 2 more answers
Is this true or false need answer asap
VLD [36.1K]
Answer: True

Step-by-Step Explanation:

=> 2x + 3y = -7 (Eq. 1)
=> -x = 2y (Eq. 2)
=> x = 1, y = -3

Substitute values of ‘x’ and ‘y’ in Eq. 1 :-

=> 2x + 3y = -7
= 2(1) + 3(-3) = -7
= 2 + -9 = -7
=> -7 = -7
=> LHS = RHS

Therefore, it is a Solution.
3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B-16%7D%20-%5Csqrt%7B-3%7D%20%5Csqrt%7B-3%7D%20-%5Csqrt%7B-4%7D%20%5Csqrt%7B-4%7D%20%
sergeinik [125]

Answer:

<h2>4(i-1)</h2>

Step-by-step explanation:

Given the expression   \sqrt{-16} - \sqrt{-3} \sqrt{-3} -\sqrt{-4} \sqrt{-4}+3i-3i^{2} +3i^{3}

On simplifying;

First we need to note that i² = -1 and √-1 = i

Substituting the values in the expression, it becomes;

= √16(√-1)-√(-3)(-3)-√(-4)(-4)+3i-3(-1)+3i(i²)

= 4i-√9-√16+3i+3-3i

= 4i-3-4+3

= 4i-4

= 4(i-1)

6 0
4 years ago
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