Answer:
Slide 1:
1. Solution = (-3,2)
<em>y = 2x - 1</em>
<em>y = 3/2x + 6</em>
2. No solution
<em>y = -4/2x + 4</em>
<em>y = -4/2x - 5</em>
Slide 2:
3. Solution = (1, -6) ONE SOLUTION
4. Solution = (-4, -1) ONE SOLUTION
p.s i attached the graphs for problems 3 and 4. The first picture is for problem 3 and the second picture is for problem 4
I really hope this helped :)
The equation that has the solution
is 3x^2 - 10x + 6 = 0
<h3>How to determine the equation?</h3>
The solution is given as:

The solution to a quadratic equation is

By comparing both equations, we have:
-b = 5
b^2 - 4ac = 7
2a = 3
Solve for b in -b = 5
b = -5
Solve for a in 2a = 3
a = 1.5
Substitute values for a and b in b^2 - 4ac = 7
(-5)^2 - 4 * 1.5c = 7
Evaluate
25 - 6c = 7
Subtract 25 from both sides
-6c = -18
Divide by - 6
c = 3
So, we have:
a = 1.5
b = -5
c = 3
A quadratic equation is represented as:
ax^2 + bx + c = 0
So, we have:
1.5x^2 - 5x +3 = 0
Multiply through by 2
3x^2 - 10x + 6 = 0
Hence, the equation that has the solution
is 3x^2 - 10x + 6 = 0
Read more about quadratic equation at:
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Answer:
TRUE
Step-by-step explanation:
tanθ = 1/cotθ
cotθ = 0 when θ = ±(1/2)π, ±(3/2)π, … ±[(2n+1)/2]π.
∴ tanθ is undefined when θ = ±[(2n+1)/2]π.
secθ = 1/cosθ
cosθ = 0 when θ = ±(1/2)π, ±(3/2)π, , …, ±[(2n+1)/2]π.
∴ secθ is undefined when θ = ±[(2n+1)/2]π.
The tangent and secant functions are undefined for the same values of θ.