ΔK = -2334.66J. The kinetic energy loss is -2334.66J.
This is an example of elastic collision which means that the two bodies remain united after the collision, as we know the amount of movement is preserved that is called conservation of momentum. So, we can write the equation as follow:
Where is the initial momentum and is the final momentum.
Substituting the values:
After the collision the bodies are united and move at the speed of 33.33 m/s.
To calculate the kinetic energy lost in the impact we only have to calculate the energy of each body before the impact and compare it with the energy of the whole after the impact.
ΔK =
ΔK =
Substituting the values:
ΔK =
ΔK =
ΔK =
ΔK =
ΔK =
ΔK =
Depends on what type of mirror that is. I am going to assume this is a plain mirror (from the phrase), which means the height and width of the object and image is exactly the same.
initial velocity=0m/s
acceleration=4.2m/s^2
time taken =5s
then final velocity
v=u+at
or, v=0+4.2*5
so final velocity is 21m/s
Answer:
x_total = 20m
Explanation:
This is an exercise in kinematics, we will look for the distance it travels during the reaction time, where there is no braking, and then the distance during the deceleration.
Distance traveled during response time
v = x₁ / t
x₁ = v t
let's calculate
x₁ = 10 0.75
x₁ = 7.5 m
Now we calculate the distance during braking, the final speed is zero (v = 0)
v² = v₀² - 2 a x₂
x₂ = v₀² / 2 a
let's calculate
x₂ = 10² / (2 4)
x₂ = 12.5m
the total stopping distance is
x_total = x₁ + x₂
X_total = 7.5 + 12.5
x_total = 20m
A. Acceleration.
acceleration is m/s^2. speed is m/s