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Alik [6]
3 years ago
5

This graph represents an exothermic reaction. What does it show about the

Physics
1 answer:
Zanzabum3 years ago
8 0

The answer is A

Just did it

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Marta, Cato, and Juan plan a skit to illustrate one of the methods of charging. Marta and Cato are walking together. Each has on
sveta [45]

Answer:

Option D.

Explanation:

Methods of charging:

1. By friction: when two materials of different electro-negativities rub against each, electrons transfer from one material to another.

2. By induction: When a charged body is brought near an uncharged body, the later gets polarized.

3. By conduction: when electrons from one body to another uncharged while contact, it is known as charging by conduction.

Here, a flower is analogous to an electron. A box of candy is positive charge. A bouquet of flowers is like a charged body which is brought near an uncharged body. It induces charge on ti it by causing it to transfer electron to another.

Thus, option D is correct.

8 0
4 years ago
Type of force that keep objects moving in a circle or arv​
Svetlanka [38]

Answer: a net force

7 0
3 years ago
An insulated beaker with negligible mass contains liquid water with a mass of 0.285 kg and a temperature of 75.2 ∘C How much ice
GrogVix [38]

Answer:

Explanation:

We shall apply the theory of

heat lost = heat gained .

heat lost by water = mass x specific heat x temperature diff

= .285 x 4190 x ( 75.2 - 32 ) = 51587.28 J  

heat gained by ice to attain temperature of zero

= m x 2100 x 22.8 = 47880 m

heat gained by ice in melting = latent heat x mass

= 334000m

heat gained by water at zero to become warm at 32 degree

= m x 4190 x 32 = 134080 m

Total heat gained = 515960 m

So

515960 m = 51587.28

m = .1 kg

= 100 gm

4 0
4 years ago
ANSWER As Soon As Possible
klemol [59]

The image is blank

Explanation:

8 0
3 years ago
Read 2 more answers
A polarized beam of intensity Io is directed into a device consisting of two polarizers. The beam is vertically polarized, and t
timama [110]

Answer:

Explanation:

The intensity of polarised light after polarization through angle θ

I = I₀ cos²θ

Here θ = 23 for first polariser

Intensity after first polarisation

= I₀ cos²23 = .846 I₀

For second polariser θ = 90 - 23 = 67 degree

Intensity after second polarisation

= .846 I₀ cos²67 =  .13 I₀ .

3 0
3 years ago
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