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pashok25 [27]
4 years ago
13

Astronaut rachel leaves earth in a spaceship at a speed of 0.960c relative to an observer on earth. rachel's destination is a st

ar system 14.4 light-years away (one light-year is the distance light travels in one year). according to rachel, how long does the trip take?
Physics
1 answer:
insens350 [35]4 years ago
4 0
Utilizing Lorentz factor;

Lorentz factor = Sqrt (1-u^2/c^2), where u = initial velocity, c = speed of light

But, u/c = 0.960

Therefore,
Lorentz factor = Sqrt (1-0.960^2) = 0.28

For an observer,
t = (Distance to the star*Lorentz factor)/ (u/c) = (14.4*0.28)/0.96 = 4.2 years
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Fill in the blank.
BabaBlast [244]

Answer:B

Explanation:The earth will keep moving unless acted up on by a force.

4 0
4 years ago
An object has a mass of 12kg. On Planet A, the object weighs 117.6 N. Is the force of gravity on Planet A equal to, less than or
kiruha [24]
Well I don't know !
Let's work it out:

       Weight = (mass) x (local acceleration of gravity)

         117.6 N  =  (12 kg) x (gravity)

         Gravity on Planet A  =  (117.6 N) / (12 kg)

                                       =      9.8 m/s²  exactly

The gravity on Planet-A is so close to Earth gravity
that nobody could ever tell the difference without
making sensitive measurements.
They are essentially equal.
4 0
3 years ago
A ladder 7.60 m long leans against an exterior wall. If the ladder is inclined at an angle of 68.0° to the horizontal, what is t
nata0808 [166]

Answer:

2.85 m

Explanation:

From trigonometry,

Cosine = Adjacent/Hypotenuse

Assuming, The wall, the ladder and the ladder forms a right angle triangle as shown in fig 1, in the diagram attached below.

cos∅ = a/H....................... Equation 1

Where ∅ = Angle the ladder makes with the horizontal, a = The horizontal distance from the bottom of the ladder to the wall, H = The length of the ladder.

make a the subject of the equation

a = cos∅(H)..................... Equation 1

Given: ∅ = 68 °, H = 7.6 m.

Substitute into equation 2

a = cos(68)×7.6

a = 0.375×7.6

a = 2.85 m.

Hence the horizontal distance from the bottom of the ladder to the wall = 2.85 m

8 0
3 years ago
Describe what’s going on in position-time graphs 1 , 3, &5
Verizon [17]

Answer:

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7 0
3 years ago
Two small plastic spheres are given positive electrical charges. When they are 16.0 cm apart, the repulsive force between them h
Drupady [299]

Answer:

q = 7.542 x 10⁻⁷ C = 754.2 nC

Explanation:

The Coulomb's Law gives the magnitude of the force of attraction or repulsion between two charges:

F = kq₁q₂/r²

where,

F = Force of attraction or repulsion = 0.2 N

k = Coulomb's Constant = 9 x 10⁹ N m²/C²

r = distance between charges = 16 cm = 0.16 m

q₁ = magnitude of 1st charge

q₂ = magnitude of 2nd charge

Since, both charges are said to be equal here.

q₁ = q₂ = q

Therefore,

0.2 N = (9 x 10⁹ N m²/C²)q²/(0.16 m)²

(0.2 N)(0.16 m)²/(9 x 10⁹ N m²/C²) = q²

q = √(5.88 x 10⁻¹³ C²)

<u>q = 7.542 x 10⁻⁷ C = 754.2 nC</u>

7 0
3 years ago
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