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hodyreva [135]
3 years ago
11

F x and r are inversely proportional and x = 9 when r = 72, then what is x when r = 40?

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

16.2

Step-by-step explanation:

r = k/x

  • when x = 9 and r = 72 ,

72 = k/9

k = 72*9

When r = 40 ,

x = k/r

x = 72*9/40 = 16.2

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Answer:

Circle A - 1 right angle

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Step-by-step explanation:

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3 years ago
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-4k + 2(5k − 6) = −3k – 48
nalin [4]

Answer:

k = -4

Step-by-step explanation:

-4k + 2(5k − 6) = −3k – 48

Distribute on the left side.

-4k + 10k - 12 = -3k - 48

Combine like terms on the left side.

6k - 12 = -3k - 48

Add 3k to both sides.

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Determine whether a figure with the given vertices is a rectangle using the Distance Formula.
Alex Ar [27]

Answer:

Yes; Opposite sides are congruent, and diagonals are congruent.

Step-by-step explanation:

we have

A(4, -7), B(4, -2), C(0, -2), D(0, -7)

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the length of the sides

<u><em>Find the distance AB</em></u>

substitute the values

d=\sqrt{(-2+7)^{2}+(4-4)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

AB=5\ units

<u><em>Find the distance BC</em></u>

substitute the values

d=\sqrt{(-2+2)^{2}+(0-4)^{2}}

d=\sqrt{(0)^{2}+(-4)^{2}}

BC=4\ units

<u><em>Find the distance CD</em></u>

substitute the values

d=\sqrt{(-7+2)^{2}+(0-0)^{2}}

d=\sqrt{(-5)^{2}+(0)^{2}}

CD=5\ units

<u><em>Find the distance AD</em></u>

substitute the values

d=\sqrt{(-7+7)^{2}+(0-4)^{2}}

d=\sqrt{(0)^{2}+(-4)^{2}}

AD=4\ units

Compare the length sides

AB=CD

BC=AD

therefore

Opposite sides are congruent

step 2

Find the length of the diagonals

<u><em>Find the distance AC</em></u>

substitute the values

d=\sqrt{(-2+7)^{2}+(0-4)^{2}}

d=\sqrt{(5)^{2}+(-4)^{2}}

AC=\sqrt{41}\ units

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substitute the values

d=\sqrt{(-7+2)^{2}+(0-4)^{2}}

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Compare the length of the diagonals

AC=BD

therefore

Diagonals are congruent

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ValentinkaMS [17]
2m-5-5= -3m +15
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m= 25/5
m=5
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