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3 years ago

I need help on 3-6a=9-6a

Mathematics

1 answer:

MrRissso [65]3 years ago

6 0

Answer:

3 = 9

Step-by-step explanation:

Simplifying 3 + -6a = 9 + -6a Add '6a' to each side of the equation. 3 + -6a + 6a = 9 + -6a + 6a Combine like terms: -6a + 6a = 0 3 + 0 = 9 + -6a + 6a 3 = 9 + -6a + 6a Combine like terms: -6a + 6a = 0 3 = 9 + 0 3 = 9 Solving 3 = 9 Couldn't find a variable to solve for.

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marissa [1.9K]

Answer:

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Step-by-step explanation:

x=22°(alternate angles are equal)

y=50°(angle sum in triangle is 180°)

z=108°

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3 years ago

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DedPeter [7]

Answer:

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3 years ago

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3 years ago

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babymother [125]

125 is equivalent to

1.25

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3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$