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yanalaym [24]
3 years ago
7

Work out the m and c for the line 3y+2x=-1

Mathematics
1 answer:
Mademuasel [1]3 years ago
8 0

Answer:

m = -2/3 and b = -1/3

Step-by-step explanation:

Write the equation of this line in slope-intercept form.  Then m = slope and b = y-intercept and the basic equation is y = mx + b.

Solving 3y+2x=-1 for y, we get 3y = -2x - 1, or y = (-2/3)x - 1/3

Here we can easily see that m = -2/3 and b = -1/3.

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The diagram shows the rectangle ABCD, where A is (3,2) and B is (1,6).
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(i)
A(3,2),B(1,6)
\\
\\m_{AB}= \frac{6-2}{1-3}=-2
\\
\\m_{BC}m_{AB}=-1
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\\m_{BC}= \frac{-1}{m_{AB}} = \frac{-1}{-2}= \frac{1}{2}  
\\
\\B(1,6)\Rightarrow x_1=1,y_1=6
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\\BC:y-y_1=m_{BC}(x-x_1)
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\\
\\2y-12=x-1
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(ii)
AC:y=x-1
\\BC:x-2y+11=0
\\
\\C=AC\cap BC
\\
\\x-2(x-1)+11=0
\\x-2x+2+11=0
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(iii)
A(3,2)B(1,6),C(13,12)
\\P=2(d(A,B)+d(B,C))
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\\d(A,B)= \sqrt{(1-3)^2+(6-2)^2}= \sqrt{20}  =2 \sqrt{5} 
\\
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3 years ago
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Answer:

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