Quadratic is the y=2x^2
that is the parabola one
when will the exponential one be higher than the parabola?
that is, hmm, find the intersection points
we can see that x=1 is an intersection point
we see that it is between the intersection points
if we use our calculator
intsersect at x=-0.578621 and 1
so it is the one from -0.5 to 1
that is the 3rd option
-0.5≤x<1
By Hand
Step 1:
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2:
Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3:
Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4:
Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5:
Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
Answer:
Assuming you want the answer in slope-intercept form, it’s <u>y = -5x + 11</u>
Step-by-step explanation:
So we have to first use point-slope form, y - y1 = m (x - x1)
If we plug the numbers in we get...
y + 4 = -5 (x - 3) (take out parenthesis)
y + 4 = -5x + 15 (now subtract 4 from 15)
<u>y = -5x + 11</u>
I think this is right
Quadratic formula: x equals negative b plus or minus the square root of b squared minus 4 ac all over 2a
a=2 b=5 c=1
x=(-5+/5^2-4(2)(1))/2(2)
-5+/25-8/4
-5+/17/4
(-5+4.12)/4
-0.877/4
-0.219
x=(-5-/5^2-4(2)(1))/2(2)
-5-/25-8/4
-5-/17/4
(-5-4.12)/4
-9.12/4
-2.28
x=-0.219 or x=-2.28
