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Kisachek [45]
2 years ago
12

Simplify (5p+1.49)-(2p+6.49) Thank you!

Mathematics
1 answer:
Xelga [282]2 years ago
5 0
5p+1.49-2p-6.49
Combine like terms
3p+1.49-6.49
=3p-5



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Hi, can you help me to solve this exercise, please!
Yuri [45]

Trigonometric Identities.

To solve this problem, we need to keep in mind the following:

* The tangent function is negative in the quadrant II

* The cosine (and therefore the secant) function is negative in the quadrant II

* The tangent and the secant of any angle are related by the equation:

\sec ^2\theta=\tan ^2\theta+1

We are given:

\text{tan}\theta=-\frac{\sqrt[]{14}}{4}

And θ lies in the quadrant Ii.

Substituting in the identity:

\begin{gathered} \sec ^2\theta=(-\frac{\sqrt[]{14}}{4})^2+1 \\ \text{Operating:} \\ \sec ^2\theta=\frac{14}{16}+1 \\ \sec ^2\theta=\frac{14+16}{16} \\ \sec ^2\theta=\frac{30}{16} \end{gathered}

Taking the square root and writing the negative sign for the secant:

\begin{gathered} \sec ^{}\theta=\sqrt{\frac{30}{16}} \\ \sec ^{}\theta=-\frac{\sqrt[]{30}}{4} \end{gathered}

5 0
11 months ago
Factor each of the following expressions into two binomials.
Anestetic [448]
Answer:

Explanation:

1.
x^2 - 10x + 24
= (x - 6)(x - 4)

2.
x^2 - 12x + 27
= (x - 9)(x - 3)

3.
x^2 - 13x + 36
= (x - 9)(x - 4)

4.
x^2 - 5x - 14
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5.
x^2 + x - 20
= (x + 5)(x - 4)

6.
x^2 - 3x - 40
= (x - 8)(x + 5)

7.
x^2 + 2x - 48
= (x - 8)(x + 6)

8.
x^2 + 10x - 24
= (x - 2)(x + 12)

9.
x^2 - 7x - 44
= (x - 11)(x + 4)

10.
x^2 + x - 2
= (x + 2)(x - 1)

11.
x^2 + 2x + 1
= (x + 1)(x + 1)

12.
x^2 - x - 6
= (x - 3)(x + 2)
7 0
2 years ago
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goldenfox [79]
What’s the question?
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1. Albert Einstein is driving down a country road at the speed of light. Just kidding. He's
dezoksy [38]

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Step-by-step explanation:

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2 years ago
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Solve for x
Ivan

9514 1404 393

Answer:

  x = 4

Step-by-step explanation:

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3 years ago
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