VVI с d не H a IX M b Y K N Z G

TBH, i am not sure what im doing. Here is a pic of the question.

tatyana61 [14]

Answer:

7

Step-by-step explanation:

The order of operations tells you to start any evaluation by looking at the innermost set of parentheses first.

Here, that means your first step is to find the value of h(-3). You do that by finding the input (x) value -3 in the table for h(x), and locating the corresponding output, h(x), which is 2.

Now, the problem becomes evaluating g(2).

You do the same thing for that function: locate the input x=2 in the table for g(x) and find the corresponding output: 7.

Now, you know ...

g(h(-3)) = g(2) = 7

4 0

2 years ago

Write the equation of a Line that is perpendicular to y=5/2x+3 and passes

koban [17]

Answer:

Step-by-step explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

$m_{1}=\frac{5}{2}\\\\m_{1}*m_{2}=-1\\\\$

$m_{2}=$ -1 ÷ $m_{1}$

= $-1*\frac{2}{5}=\frac{-2}{5}$

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

y - [5] = $\frac{-2}{5}(x - [-3])\\$

$y+5=\frac{-2}{5}x + 3*\frac{-2}{5}\\\\y+5=\frac{-2}{5}x-\frac{6}{5}\\\\ y =\frac{-2}{5}x-\frac{6}{5}-5\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{5*5}{1*5}\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{25}{5}\\\\\\ y=\frac{-2}{5}x-\frac{31}{5}$