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Luden [163]
3 years ago
10

Pls help on 11

Mathematics
1 answer:
Julli [10]3 years ago
8 0
I don't Really know much about this stuff but I'm guessing its adjacent...
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10.
timama [110]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Simplify the sum. (7u3 + 8u2 + 7) + (8u3 – 3u + 7)
bazaltina [42]
= (7u³ + 8u² + 7) + (8u³ - 3u + 7)
Operate like terms together:

= 7u³ + 8u³ + 8u² - 3u + 7 + 7
= 15u³ + 8u² - 3u + 14

In short, Your Answer would be: 15u³ + 8u² - 3u + 14

Hope this helps!
8 0
2 years ago
Read 2 more answers
Use a double angle identity to rewrite the formula r(Θ)=<img src="https://tex.z-dn.net/?f=1%2F16v%5E2sin%28theta%29cos%28theta%2
Artist 52 [7]

Answer:

1/32v²sin2θ

Step-by-step explanation:

Given the expression r(theta) = 1/16v²sinθcosθ

According to double angle of trigonometry identity;

Sin2θ = sin(θ+θ)

Sin2θ = sinθcosθ + cosθsinθ

Sin2θ = 2sinθcosθ

sinθcosθ = sin2θ/2 ... **

Substituting equation ** into the question

1/16v²sinθcosθ = 1/16v²(sin2θ/2)

1/16v²sinθcosθ = 1/2×1/16v²(sin2θ)

1/16v²sinθcosθ = 1/32v²sin2θ

Hence using the double angle identity, the equivalent expression is 1/32v²sin2θ

7 0
3 years ago
3s – 12 = -21<br> Solve for s
NISA [10]

Answer:

S= -3

Step-by-step explanation:

3s-12=-21

3s= -21+12

3s= -9

s= -9/3

s= -3

7 0
3 years ago
Read 2 more answers
Quick question if I had a problem that was sin x = 18.9/20 =.945 how would I inverse sin of both sides ?
Black_prince [1.1K]

Step-by-step explanation:

gabcjxjdjdidifkfdjdjdjdddd

8 0
2 years ago
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