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Licemer1 [7]
3 years ago
5

A line has a slope of –3 and a y-intercept of (0, –1). What is the equation of the line that is parallel to the given line and p

asses through the point (–3, 1)?
A.
y = –3x – 8
B.
y = 3x + 10
C.
y = –3x + 4
Mathematics
1 answer:
givi [52]3 years ago
6 0
Well, the first line has a slope of -3, and runs through 0, -1.

a line parallel to that one, will have the same exact slope of -3.

now, we know about this other parallel line that it runs through -3,1, and of course, since is parallel, it has a slope of -3

\bf \begin{array}{ccccccccc}
&&x_1&&y_1\\
&&(~ -3 &,& 1~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies -3
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=-3[x-(-3)]
\\\\\\
y-1=-3(x+3)
\implies 
y-1=-3x-9\implies y=-3x-8
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